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jek_recluse [69]
3 years ago
14

How does using visual models help us understand dividing fractions by whole numbers?

Mathematics
1 answer:
aleksley [76]3 years ago
3 0
My friend have the same problem can you let me know when you find out ? I
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Why resultant magnitude by using Pythagorean theorem is different than using ( x,y )components addition vectors ???
Andreyy89

9514 1404 393

Explanation:

Your different answers came about as a result of an error you made in the Pythagorean theorem calculation.

  √(100 +100) = √200 = 14.142 . . . . same as vector calculation

4 0
2 years ago
Um feirante usava uma balança de dois pratos com pesos de 2 kg, 1 kg, 500 g, 200 g
andrew-mc [135]

Answer:

hola si mui bein

Step-by-step explanation:

3 0
2 years ago
Use the substitution method to solve the following system of equations: 3x + 5y = 3 x + 2y = 0 (1 point) (1, 1) (6, −3) (6, 1) (
PtichkaEL [24]

Step-by-step explanation:

Given.

3x+5y=3

x+2y=0

Take the second equation and subtract 2y to both sides.

(x+2y)-2y=0-2y

x=-2y

Substitute x into the first equation and simplify.

3x+5y=3

3(-2y)+5y=3

-6y+5y=3

-y=3

Invert.

y=-3

Substitute Y into your second equation.

x+2y=0

x+2(-3)=0

x-6=0

Add -6 to both sides.

(x-6)+6=0+6

x=6

Answer:

(6, -3)

6 0
2 years ago
How many extraneous solutions does the equation below have? StartFraction 9 Over n squared 1 EndFraction = StartFraction n 3 Ove
BigorU [14]

The equation has one extraneous solution which is n ≈ 2.38450287.

Given that,

The equation;

\dfrac{9}{n^2+1} =\dfrac{n+3}{4}

We have to find,

How many extraneous solutions does the equation?

According to the question,

An extraneous solution is a solution value of the variable in the equations, that is found by solving the given equation algebraically but it is not a solution of the given equation.

To solve the equation cross multiplication process is applied following all the steps given below.

\rm \dfrac{9}{n^2+1} =\dfrac{n+3}{4}\\\\9 (4) = (n+3) (n^2+1)\\\\36 = n(n^2+1) + 3 (n^2+1)\\\\36 = n^3+ n + 3n^2+3\\\\n^3+ n + 3n^2+3 - 36=0\\\\n^3+ 3n^2+n -33=0\\

The roots (zeros) are the  x  values where the graph intersects the x-axis. To find the roots (zeros), replace  y

with  0  and solve for  x. The graph of the equation is attached.

n  ≈  2.38450287

Hence, The equation has one extraneous solution which is n  ≈  2.38450287

For more information refer to the link.

brainly.com/question/15070282

5 0
2 years ago
Divide z by 11. Then, add 8.
yulyashka [42]
This may be the answer,hope it helps

8 0
3 years ago
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