The sequence 3, 1,1/3 is a geometric sequence
The 7th term of the sequence is 1/243
<h3>How to determine the 7th term?</h3>
The sequence is given as:
3, 1,1/3
The above sequence is a geometric sequence with the following parameters:
- First term, a= 3
- Common ratio, r = 1/3
The nth term is then calculated as:
Tn = ar^(n-1)
So, the 7th term is:
T7 = ar^6
Substitute known values
T7 = 3 * (1/3)^6
This gives
T7 = 1/3^5
Evaluate
T7 = 1/243
Hence, the 7th term of the sequence is 1/243
Read more about geometric sequence at:
brainly.com/question/24643676
Answer:
1- %50
0.2008
Step-by-step explanation:
0.0008 1/5
(0.0008*5)+1=0.004+1=1.004/5
0.2008
I think you mean "if the points <span>(2,5), (3,2) and (4,5) satisfy an unknown 3rd degree polynomial, what is the polynomial?"
Since 3 roots {2, 3, 4} are known, we might begin by assuming that this poly would have the form y = ax^3 + bx^2 + cx + d (which has three factors). Unfortunately, three roots are not enough to determine all four constants {a, b, c, d}.
So, let's assume, instead, that the poly would have the form y = ax^2 + bx + c. Three given points should make it possible to determine {a, b, c}.
(2,5): 5 = a(2)^2 + b(2) + c => 5 = 4a + 2b + c
(3,2): 2 = a(3)^2 + b(3) + c => 2 = 9a + 3b + 5 - 4a - 2b
(4,5): 5 = a(4)^2 + b(4) + c => 5 = 16a + 4b + 5 - 4a - 2b
Now we have two equations in a and b alone, which enables us to solve for a and b:
</span>2 = 9a + 3b + 5 - 4a - 2b becomes -3 = 5a + b
<span>and
</span>5 = 16a + 4b + 5 - 4a - 2b becomes 0 = 12a + 2b, or 0 = 6a + b, or 0=-6a-b
<span>
Adding this result to -3 = 5a + b, we get -3 = -a, so a =3.
Thus, since -3 = 5a + b, -3 = 5(3) + b, so b = -18
All we have to do now is to find c. Let's do this using </span>5 = 4a + 2b + c.
We know that a = 3 and b = -18, so this becomes 5 = 4(3) + 2(-18) + c.
Thus, 5 = 12 - 36 + c, or c = 29.
With a, b and c now known, we can write the poly as y = 3x^2 - 18x + 29.
Now the only thing to do remaining is to verify that each of the three given points satsifies y = 3x^2 - 18x + 29. Try this, please.
