Question

Emmanuel added two integers Which condition will always give Emmanuel a negative solution when he adds two integers? Both integers have negative values Both integers have positive values O. One integer has a positive value, and one integer has a negative value O The values of the two integers are opposites

Answer 1

Both integers have negative values

Explanation

Let

x and y represents the number

so, the options are

$\begin{gathered} +\text{ + +} \\ +\text{ + -} \\ -\text{ + +} \\ -\text{ +-} \end{gathered}$

a) Both integers have negative values Both integers

$-x-y=-(x+y)\rightarrow you\text{ will always get a negative number}$

b) Both integers have positive values

$x+y=+\text{ + += you will always get a positive number}$

c)One integer has a positive value, and one integer has a negative value

$\begin{gathered} -x+y\text{ or x-y} \\ the\text{ sign of the result depends on the greates absolute value, it means the answer will have the same of the bigger number( absolute value)} \end{gathered}$

d)The values of the two integers are opposites​

as the point C , the sign depends on the bigger number

for example

$\begin{gathered} 8-5=3\text{ positive because 8 is the bigger} \\ 5-8=-3\text{ negative because (-8) is has the bigger absolute value} \end{gathered}$

so, the answer is Both integers have negative values

I hope this helps you