Answer:
1. <u>Phosphoribosyl</u> amine
2. <u>glycinamide ribonucleotide (GAR), a formyl group</u>
3. F<u>ormylglycinamide ribonucleotide (FGAR), an amino group</u>
4. C<u>arboxyaminoimidazole ribonucleotide (CAIR), an amino group.</u>
Explanation:
1. <u>Phosphoribosyl</u> amine will accumulate in bacteria that lack glycine.
2. The intermediate <u>glycinamide ribonucleotide (GAR)</u> will build up in the absence of tetrahydrofolate.
N10‑Formyltetrahydrofolate donates <u>a formyl group</u> to the substrate
3. F<u>ormylglycinamide ribonucleotide (FGAR) </u>will accumulate in the absence of glutamine.
Glutamine donates <u>an amino group</u>
4.<u> </u>The intermediate <u>carboxyaminoimidazole ribonucleotide (CAIR)</u> will accumulate when aspartate is lacking.
Aspartate donates <u>an amino group.</u>
It is very True to make the function of the cell work well
C. The question is hinting at the similarities between how single cellular organisms maintain homeostasis by regulating water levels the same way the kidney does for multi cellular humans.
Nerve cells, also called neurons, are specialized cells for the nervous system that is responsible for movement and response system. This is done through action potentials that lets the neurons generate a electric synapse to that received stimuli.
When there is an unequal amount of charges between the sides of the neurons, this can be described as diffusion potential or the resting potential.
The answer is D. All of the above.. I just took the test (:
