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PIT_PIT [208]
3 years ago
10

Abandoned mines frequently fill with water. Before an abandoned mine can be reopened, the water must be pumped out. The size of

pump required depends on the depth of the mine. If pumping out a mine that is D feet deep requires a pump that pumps a minimum of + 4D – 250 gallons per minute, pumping out a mine that is 150 feet deep would require a pump that pumps a minimum of how many gallons per minute?
Mathematics
1 answer:
ale4655 [162]3 years ago
5 0

Answer:

350gallons /minute

Step-by-step explanation:

D = minimun depth of mine

4D-250 = minimum gallon per minute required to pump

4(150)- 250= 350gallon/minute

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Step-by-step explanation:

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A

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3 years ago
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solong [7]
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Finally, we need to divide both sides by 3, to get rid of the coefficient that is being multiplied to x.

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Therefore, the number that you are trying to find is 32.
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