All categories

3 years ago

???? Help plz ?…. It’s a grade

Mathematics

1 answer:

Aleks [24]3 years ago

4 0

Answer:

Yes it does show a dilation

You might be interested in

Help ASAP I’ll mark you as brainlister

liraira [26]

Answer:

about 0.10 cents a unit

Step-by-step explanation:

If I'm wrong, I'm sorry!!

I hope you have a great day! Good luck with your math!

6 0

3 years ago

Solve using substitution<br><br> y=1/2x<br> x+4y=18

Aleks [24]

Answer:

The solution set is (6,3)

Step-by-step explanation:

Begin by multiplying equation 1 by 2. You'll see why in a moment

2y = 2*(1/2) x

2y = x

Substitute this value into equation 2.

2y + 4y = 18 Combine like terms on the left

6y = 18 Divide both sides by 6

6y/6 = 18/6 Do the division

y = 3

To solve for x just use the top equation

y = 1/2x

3 = 1/2x Multiply by 2

3*2 = x

x = 6

7 0

3 years ago

..................................................................

serious [3.7K]

Answer:

Hello?

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Three partners in a business venture have incurred a debt of $9,876. Use an integer to express the amount of debt for each one.

Gelneren [198K]

Answer:

$3292

$9,876/3 = 3292

3 0

3 years ago

In parallelogram ABCD below, line AC is a diagonal, the measure of angle ABC is 40 degrees, and the measure of angle ACD is 57 d

Lorico [155]

Answer:

The measure of angle CAD is 83 degrees.

Step-by-step explanation:

Given information: ABCD is a parallelogram, AC is a diagonal, $\angle ABC=40^{\circ}$ and $\angle ACD=57^{\circ}$ .

The opposite sides of parallelogram are congruent.

The diagonal AC divides the parallelogram in two congruent triangles.

In triangle ABC and ADC,

$AB\cong CD$ (Opposite sides of parallelogram)

$\angle ABC\cong \angle ADC$ (Opposite angles of parallelogram)

$BC\cong DA$ (Opposite sides of parallelogram)

By SAS postulate,

$\triangle ABC\cong \triangle CDA$

Since we know that opposite angles of parallelogram are equal, therefore

$\angle ABC\cong \angle ADC$

$\angle ADC=40^{\circ}$

According to the angle sum property the sum of interior angles of a triangle is 180 degrees.

$\angle CAD+\angle ACD+\angle ADC=180^{\circ}$

$\angle CAD+57^{\circ}+40^{\circ}=180^{\circ}$

$\angle CAD=83^{\circ}$

Therefore the measure of angle CAD is 83 degrees.

6 0

3 years ago