From the given information; Let the unknown different positive integers be (a, b, c and d).
An integer is a set of element that are infinite and numeric in nature, these numbers do not contain fractions.
Suppose we make an assumption that (a) should be the greatest value of this integer.
Then, the other three positive integers (b, c and d) can be 1, 2 and 3 respectively in order to make (a) the greatest value of the integer.
Therefore, the average of this integers = 9
Mathematically;



By cross multiplying;
6+a = 9 × 4
6+a = 36
a = 36 - 6
a = 30
Therefore, we can conclude that from the average of four positive integers which is equal to 9, the greatest value for one of the selected integers is equal to 30.
Learn more about integers here:
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To the nearest ten, 829 would become <em><u>830</u></em> because the ones digit (9) is closer to 30 than it is to 20. So we would round up.
To round to the nearest hundred, we look at the tens and ones digit. 29 is less than 50 so we would have to round down to <em><u>800</u></em> instead of rounding up to 900.
Hope that helps :)
Given:
Speed limit on a highway is 110 km per hour.
Let x be the speed of the car in time 't'

time when taken for a car to travel 132km.

It takes minimum 1 hour 12 minutes
Answer:

Step-by-step explanation:

Remember that
.

When you multiply powers with the same base, add the exponents. Do this in the denominator.


When you divide powers with the same base, subtract the exponents.


Answer:
I also got 616, what is the answer??
Step-by-step explanation: