I think the surface area would be 740 square meters!!!
Answer:
3.6 hours
Step-by-step explanation:
To determine the time needed if they are working together, we use the formula
1/Ta + 1/Tb = 1 Tc
where Ta is the the time for the first item working alone
Tb is the time for the second item alone
Tc is the time for them working together
1/9 + 1/6 = 1/Tc
I multiply by 54Tc to clear the fractions
54Tc (1/9 + 1/6) = 1/Tc *54Tc
6Tc + 9 Tc = 54
Combine like terms
15Tc = 54
Divide each side by 15
15 Tc /15 = 54/15
Tc =3.6 hours
We are given the statement that the strength, S, of a beam of width w andheight h is proportional to wh2. hence using k as the proportionality constant, the equation is S = k wh2. the exact width and height can be determined by applying optimization to the problem. optimization is taking the first derivative of an equation and equating then to zero
Answer:
The value of the single logarithm is -11 ⇒ answer B
Step-by-step explanation:
* Lets revise the rule of the logarithmic functions
# ㏒ a + ㏒ b = ㏒ ab
# ㏒ a - ㏒ b = ㏒ a/b
# ㏒ a^n = n ㏒ a
# ㏒ 1 = 0
* Now lets solve the problem
∵ ![log_{b}(\frac{A^{5}C^{2}}{D^{6}})](https://tex.z-dn.net/?f=log_%7Bb%7D%28%5Cfrac%7BA%5E%7B5%7DC%5E%7B2%7D%7D%7BD%5E%7B6%7D%7D%29)
- Change the single logarithm to an expression by change the
multiplication to addition and the division to subtraction
∵ ![log_{b}A^{5}=5log_{b}A](https://tex.z-dn.net/?f=log_%7Bb%7DA%5E%7B5%7D%3D5log_%7Bb%7DA)
∵ ![log_{b}C^{2}=2log_{b}C](https://tex.z-dn.net/?f=log_%7Bb%7DC%5E%7B2%7D%3D2log_%7Bb%7DC)
∵ ![log_{b}D^{6}=6log_{b}D](https://tex.z-dn.net/?f=log_%7Bb%7DD%5E%7B6%7D%3D6log_%7Bb%7DD)
∴ The single logarithm = ![5log_{b}A+2log_{b}C-6log_{b}D](https://tex.z-dn.net/?f=5log_%7Bb%7DA%2B2log_%7Bb%7DC-6log_%7Bb%7DD)
* Now lets substitute the values
∵ ![log_{b}A=3;===log_{b}C=2;===log_{b}D=5](https://tex.z-dn.net/?f=log_%7Bb%7DA%3D3%3B%3D%3D%3Dlog_%7Bb%7DC%3D2%3B%3D%3D%3Dlog_%7Bb%7DD%3D5)
- Substitute the values into the expression
∴ The value = 5(3) + 2(2) - 6(5) = 15 + 4 - 30 = -11
* The value of the single logarithm is -11
Answer:
In case of compound interest: Final Amount![=1954.72](https://tex.z-dn.net/?f=%3D1954.72)
In case of simple interest: Final Amount![=1846](https://tex.z-dn.net/?f=%3D1846)
Step-by-step explanation:
<u><em>If Compound Interest is taken:</em></u>
![A=P(1+\frac{r}{100})^n\\\\Where\ P:Initial\ Amount, A:Final\ Amount,\ r:interset\ rate\ and\ n:number\ of\ years](https://tex.z-dn.net/?f=A%3DP%281%2B%5Cfrac%7Br%7D%7B100%7D%29%5En%5C%5C%5C%5CWhere%5C%20P%3AInitial%5C%20Amount%2C%20A%3AFinal%5C%20Amount%2C%5C%20r%3Ainterset%5C%20rate%5C%20and%5C%20n%3Anumber%5C%20of%5C%20years)
![Here\ P=1300,\ r=6\%,\ n=7\\\\A=1300(1+\frac{6}{100})^7\\\\A=1300(1+0.06)^7\\\\A=1300(1.06)^7\\\\A=1954.72](https://tex.z-dn.net/?f=Here%5C%20P%3D1300%2C%5C%20r%3D6%5C%25%2C%5C%20n%3D7%5C%5C%5C%5CA%3D1300%281%2B%5Cfrac%7B6%7D%7B100%7D%29%5E7%5C%5C%5C%5CA%3D1300%281%2B0.06%29%5E7%5C%5C%5C%5CA%3D1300%281.06%29%5E7%5C%5C%5C%5CA%3D1954.72)
<u><em>If Simple Interest is taken:</em></u>
<u><em /></u>
<u><em /></u>
<u><em /></u>
<u><em /></u>