The formula equals 16t squared is used to approximate the distance s, in feet, that an object falls freely from rest in t seco
1 answer:
The equation is actually 
. Free fall is always -16t^2 as the position function. We are looking for how long it takes the object to hit the ground. In other words, the height of an object is 0 when it is laying on the ground, so how long (t) did it take to get there? We will then set that position equal to 0 and solve for t. 
. If we subtract 1437 from both sides and divide by -16, we have 
. Taking the square root of both sides gives us, rounded to the nearest tenth, t = 9.5 or t=-9.5. The 2 things in math that will never EVER be negative are time and distance/length, so -9.5 is out. That means that it took just about 9.5 seconds for the object to fall to the ground from a height of 1437 feet when pulled on by the force of gravity.
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Given:
Rectangular coordinate = (8, 6)
To convert:
Rectangular coordinate to polar coordinate with r > 0 and 0 ≤ θ < 2π.
Solution:
Let us find r:
r = 10
Now, find θ:
Cancel the common factor 2.
θ = 36.87°
The polar coordinates are (r, θ) = (10, 36.87°).