Answer:
3 and 4 are complementary because they both add up to 90
Step-by-step explanation:
Answer:
A value, or values, we can put in place of a variable (such as x) that makes the equation true.
Example: x + 2 = 7
When we put 5 in place of x we get: 5 + 2 = 7
5 + 2 = 7 is true, so x = 5 is a solution
S(8)=((100×(1−(50÷100)^(8))÷(1−50÷100)))
=199.22
Step 1
Anything divided by one gives itself.
\frac{1}{8}=-8\text{ and }\frac{-8}{1}=\frac{-12}{48}
8
1
=−8 and
1
−8
=
48
−12
Step 2
Convert -8−8 to fraction -\frac{64}{8}−
8
64
.
\frac{1}{8}=-\frac{64}{8}\text{ and }\frac{-8}{1}=\frac{-12}{48}
8
1
=−
8
64
and
1
−8
=
48
−12
Step 3
Compare \frac{1}{8}
8
1
and -\frac{64}{8}−
8
64
.
\text{false}\text{ and }\frac{-8}{1}=\frac{-12}{48}false and
1
−8
=
48
−12
Step 4
Anything divided by one gives itself.
\text{false}\text{ and }-8=\frac{-12}{48}false and −8=
48
−12
Step 5
Reduce the fraction \frac{-12}{48}
48
−12
to lowest terms by extracting and canceling out 1212.
\text{false}\text{ and }-8=-\frac{1}{4}false and −8=−
4
1
Step 6
Convert -8−8 to fraction -\frac{32}{4}−
4
32
.
\text{false}\text{ and }-\frac{32}{4}=-\frac{1}{4}false and −
4
32
=−
4
1
Step 7
Compare -\frac{32}{4}−
4
32
and -\frac{1}{4}−
4
1
.
\text{false}\text{ and }\text{false}false and false
Step 8
The conjunction of \text{false}false and \text{false}false is \text{false}false.
\text{false}false
Hint
Do the arithmetic.
Solution
\text{false}false
Answer:
Top Table because it has a sequence going on