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8_murik_8 [283]
3 years ago
12

PLEASE HELP MEE!!!!! WILL GIVE BRAINLIEST AND HANGOUTS!!!!!!!!

Mathematics
2 answers:
jeka943 years ago
7 0

Answer:

Blue line: y = -2

Red line: y = 2/3 x + 2

Perpendicular to red line: y = -3/2x + 2

Parallel to red line: y = 2/3 x + any real number



borishaifa [10]3 years ago
6 0

Answer:

Blue line is y=-2

Red line is y=\frac{2}{3}x+2.

Perpendicular to red is y=-\frac{3}{2}x+2.

Parallel to red is y=\frac{2}{3}x+5

Step-by-step explanation:

The blue line is a horizontal line through the y-axis. These lines have no slope and are written as y=0x-2 since -2 is the y-intercept. We simplify and y=-2.

The red line has a slope of 2/3 since it rises 2 units for every 3 units it runs from point to point. It has a y-intercept at 2 on the y-axis. The equation in slope-intercept is y=mx +b. We substitute. y=\frac{2}{3}x+2

To write a parallel line, we use the same slope and choose a different y-intercept. Parallel to red is y=\frac{2}{3}x+5

To write a perpendicular line, we find the negative reciprocal of the slope which is -3/2. Perpendicular to red is y=-\frac{3}{2}x+2.

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Math please help! Solve for x.
S_A_V [24]
I think the answer should be
x \geqslant 2
7 0
3 years ago
A shipment of 50,000 transistors arrives at a manufacturing plant. The quality control engineer at the plant obtains a random sa
Aleks04 [339]

Step-by-step explanation:

remember, the number of possible combinations to pick m out of n elements is C(n, m) = n!/(m! × (n-m)!)

50,000 transistors.

4% are defective, that means 4/100 = 1/25 of the whole.

so, the probability for one picked transistor to be defective is 1/25.

and the probability for it to work properly is then 1-1/25 = 24/25.

now, 500 picks are done.

to accept the shipment, 9 or less of these 500 picks must be defective.

the probability is then the sum of the probabilities to get

0 defective = (24/25)⁵⁰⁰

1 defective = (24/25)⁴⁹⁹×1/25 × C(500, 1)

= 24⁴⁹⁹/25⁵⁰⁰ × 500

2 defective = (24/25)⁴⁹⁸×1/25² × C(500, 2)

= 24⁴⁹⁸/25⁵⁰⁰ × 250×499

3 defective = 24⁴⁹⁷/25⁵⁰⁰ × C(500, 3) =

= 24⁴⁹⁷/25⁵⁰⁰ × 250×499×166

...

9 defective = 24⁴⁹¹/25⁵⁰⁰ × C(500, 9) =

= 24⁴⁹¹/25⁵⁰⁰ × 500×499×498×497×496×495×494×493×492×491 /

9×8×7×6×5×4×3×2 =

= 24⁴⁹¹/25⁵⁰⁰ × 50×499×166×71×31×55×494×493×41×491

best to use Excel or another form of spreadsheet to calculate all this and add it all up :

the probability that the engineer will accept the shipment is

0.004376634...

which makes sense, when you think about it, because 10 defect units in the 500 is only 2%. and since the whole shipment contains 4% defect units, it is highly unlikely that the random sample of 500 will pick so overwhelmingly the good pieces.

is the acceptance policy good ?

that completely depends on the circumstances.

what was the requirement about max. faulty rate in the first place ? if it was 2%, then the engineer's approach is basically sound.

it then further depends what are the costs resulting from a faulty unit ? that depends again on when the defect is usually found (still in manufacturing, or already out there at the customer site, or somewhere in between) and how critical the product containing such transistors is. e.g. recalls for products are extremely costly, while simply sorting the bad transistors out during the manufacturing process can be rather cheap. if there is a reliable and quick process to do so.

so, depending on repair, outage and even penalty costs it might be even advisable to have a harder limit during the sample test.

in other words - it depends on experience and the found distribution/probability curve, standard deviation, costs involved and other factors to define the best criteria for the sample test.

3 0
2 years ago
R=8 P=7 R+P= PLZ im stuck <br>​
mihalych1998 [28]

Answer:

15

Step-by-step explanation:

The equation is just a plug in and solve. you have your given variables and all you have to do it plug them into the matching spot and solve

R=8   P=7

 8+7=15

7 0
3 years ago
Giá trị x thoả mãn x(x − 3) + x − 3 =0 là
svet-max [94.6K]

Here we will use the trial and error method.

  • We will try putting different values of x.
<h3 /><h3>1st of all</h3><h3>x=1</h3>

\begin{gathered}\\ \sf\longmapsto 1(1-3)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto (-2)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2-2=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -4≠0\end{gathered}

<h2>Now,</h2><h3>x=2</h3>

\begin{gathered}\\ \sf\longmapsto 2(2-3)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 2(-1)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -3≠0\end{gathered}

<h2>Again,</h2><h3>x=3</h3>

\begin{gathered}\\ \sf\longmapsto 3(3-3)+3-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3(3-3)=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3×0=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 0=0\end{gathered}

<h3>☣Hence, The value of X as 3 satisfies the equation!</h3>
5 0
3 years ago
Please help me for 30 points
myrzilka [38]

Answer: 1D, 2E, 3B, 4A, 5C

Step-by-step explanation:

First, eliminate choices that cannot go together.

The "greater than" and "less than" symbols, represented by > and <, are used to show that a number is greater than another set of numbers, but not equal to the set of numbers.

The "greater than or equal to" and "less than or equal to" symbols, represented by ≥ and ≤, are used to show that a number can also be equal to a set of numbers.

On the number line, open dots are used to represent > and <.

Closed dots are used to represent  ≥ and ≤.

Using this, C, D, and E must match with 1, 2, and 5.

Dealing with 3 now:

4m ≥ 32

Divide both sides by 4 to simplify m:

m ≥ 8 - This is used to show that m is greater than or equal to 8.

This lines up with choice B: the line starts at 8 and goes onwards to positive infinity.

This means that 4 matches to A, because it is the only other option with a closed dot.

Looking at 1 (x - 5 < 2), we can simplify it very easily by adding 5 to both sides of the inequality:

x < 7 - This is used to show that x is less than 7.

This lines up with choice D: The line starts at less than 7 and goes downwards to negative infinity.

Looking at 2 (m + 24 > 20), we can do this the same way. Subtract 24 from both sides to get:

m > -4 - This is used to show that m is greater than negative 4.

This lines up with choice E: The line starts at greater than 4 and goes to positive infinity.

The last choice, choice 5, must match with choice C.

6 0
3 years ago
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