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astra-53 [7]
3 years ago
10

Describe the different ways to shift the equilibrium to the left for the following reaction. 2 A (s) + 2 BC (aq) -->. 2 AB (a

q) + C2 (g). Justify your answer TriangleH = -352 kJ
Chemistry
1 answer:
UNO [17]3 years ago
4 0
1) increase in temperature (heat up). Since the reaction is exothermic because the ΔH value is negative, it means the heat is on the right side of the reaction, in the products; if there is an increase in temperature, the reaction shift away from the heat; to the left.

2) adding any of the product to the reaction, AB or C2 will cause the reaction to shift to the left because if we increase the concentrations of any, the reaction will try to decrease them by shifting away from them and use them as reactants.

3) you could increase the pressure. when pressure increases, the reaction shift to the side with less pressure, or fewer gas moles. this reaction has zero gas moles in the left but 1 in the right. so it shifts left. One way to increase the pressure is to decrease the volume of the container.


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Chemical equilibrium between gaseous reactants and products is shown.
Vinvika [58]

Answer:

The reaction is shifted to the left.

Explanation:

  • Le Châtelier's principle states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.
  • When there is a decrease in pressure, the equilibrium will shift towards the side with more no. of moles of gas molecules of the reaction.
  • The reactants side (left) has 4.0 moles of gases and the products side (right) has 2.0 moles of gases.
  • So, decreasing the pressure will shift the reaction to the side with more moles of gas (left side).
  • <em>so, the reaction is shifted to the left.</em>

<em></em>

4 0
3 years ago
Read 2 more answers
A slice of cheese has a mass of 21 g and a volume of 15 cm3. What is the density of the cheese in units of g/cm3 and g/mL?
photoshop1234 [79]

Explanation:

First, you have to know the definition of density. Density is mass per unit volume, or D = m/V. In this problem, you are given the mass = 37 g and you are given the volume of 21 cm3. So, the density is simply m/V = 37g/21cm3 = 1.76g/cm3. It's that simple.

5 0
3 years ago
The molecule ch3-ch2-ch2-ch2-ch2-ch2-ch3 is best described as a(n) ________.
Gwar [14]

Given molecule:

CH3-CH2-CH2-CH2-CH2-CH2-CH3

- The molecule contain only C and H atoms, hence it is a hydrocarbon

- The C atoms in the linear chain are linked together by carbon-carbon single bonds, hence it is a saturated compound

- It has 7 C atoms and 16 H atoms, hence the molecular formula is C7H16

-The molecular formula can be generally represented as CnH2n+2 where n = 7. This corresponds to the general molecular formula for alkanes

The given molecule is best described as an <u>alkane</u>


7 0
3 years ago
For each of the acid–base reactions, calculate the mass (in grams) of each acid necessary to completely react with and neutraliz
LiRa [457]

Acid-base neutralization reaction is defined as reaction of acid with base to form corresponding salt and water. Strong acid and base completely neutralize each other.

(a) The acid base neutralization reaction is as follows:

HCl(aq)+NaOH(aq)\rightarrow H_{2}O(l)+NaCl(g)

From the above balanced chemical reaction, 1 mol of NaOH completely reacts with 1 mol of HCl. The mass of NaOH is given 4.85 g, convert this into number of moles as follows:

n=\frac{m}{M}

Molar mass of NaOH is 39.997 g/mol, thus,

n=\frac{4.85 g}{39.997 g/mol}=0.121 mol

Thus, 0.121 mol of NaOH reacts with same amount of HCl and number of moles of HCl will be 0.121 mol.

Since. molar mass of HCl is 36.46 g/mol, thus, mass can be calculated as follows:

m=n\times M=0.121 mol\times 36.46 g/mol=4.421 g

Therefore, 4.421 g of HCl completely reacts with 4.85 g of NaCl.

(b) The acid base neutralization reaction is as follows:

2HNO_{3}(aq)+Ca(OH)_{2}(aq)\rightarrow 2H_{2}O(l)+Ca(NO_{3})_{2}(aq)

From the above balanced chemical reaction, 1 mol of Ca(OH)_{2} completely reacts with 2 mol of  HNO_{3}. The mass of Ca(OH)_{2}   is given 4.85 g, convert this into number of moles as follows:

n=\frac{m}{M}

Molar mass of Ca(OH)_{2}  is 74.093 g/mol, thus,

n=\frac{4.85 g}{74.093 g/mol}=0.06545 mol

Thus, 0.06545 mol of Ca(OH)_{2} reacts with 2\times 0.06545 mol=0.13091 mol of HNO_{3}

Since. molar mass of HNO_{3} is 63.01 g/mol, thus, mass can be calculated as follows:

m=n\times M=0.13091 mol\times 63.01 g/mol=8.25 g

Therefore, 8.25 g of HNO_{3} completely reacts with 4.85 g of Ca(OH)_{2}.

(c) The acid base neutralization reaction is as follows:

H_{2}SO_{4}(aq)+2 KOH (aq)\rightarrow 2H_{2}O(l)+K_{2}SO_{4}(aq)

From the above balanced chemical reaction, 2 mol of KOH completely reacts with 1 mol of  H_{2}SO_{4}. The mass of KOH  is given 4.85 g, convert this into number of moles as follows:

n=\frac{m}{M}

Molar mass of KOH  is 56.1056 g/mol, thus,

n=\frac{4.85 g}{56.1056 g/mol}=0.0864 mol

Thus, 0.0864 mol of KOH reacts with \frac{0.0864 mol}{2}=0.0432 mol of H_{2}SO_{4}

Since. molar mass of H_{2}SO_{4} is 98.079 g/mol, thus, mass can be calculated as follows:

m=n\times M=0.0432 mol\times 98.079 g/mol=4.24 g

Therefore, 4.24 g of KOH completely reacts with 4.85 g of H_{2}SO_{4}.

8 0
4 years ago
Identify all statements that accurately describe the structure of the pyruvate dehydrogenase ( PDH ) complex.
Nostrana [21]

Answer:

The statements that correctly describes pyruvate dehydrogenase includes:

- Several copies each of E 1 and E 3 surround E 2.

-A regulatory kinase and phosphatase are part of the mammalian PDH complex.

-E 2 contains three domains.

Explanation:

Pyruvate dehydrogenase is a hydrolase key enzyme in glucose metabolism which converts pyruvate to acetyl- ChoA. It also forms a complex that catalyzes an irreversible reaction that is the entry point of pyruvate into the TCA cycle. Pyruvate dehydrogenase complex contains E1, E2 and E3 enzymes that transform pyruvate, NAD+, coenzyme A into acetyl-CoA, CO2, and NADH. Also, A regulatory kinase and phosphatase are part of the mammalian PDH complex and E 2 contains three domains.

5 0
3 years ago
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