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AURORKA [14]
3 years ago
13

During the light-independent reaction, carbon dioxide is fixed by adding it to a A. 2-carbon compound B. 3-carbon compound C. 4-

carbon compound D. 5-carbon compound
Chemistry
2 answers:
Scrat [10]3 years ago
8 0
During the light independent reaction, carbon dioxide is fixed by adding it to a <span>5-carbon compound</span>
STatiana [176]3 years ago
5 0

Answer:

3 carbon compound.

Explanation:

During photosyntesis process, in the light -independent reaction, the carbon dioxide is going to fixed to the compound called 3 - phosphoglycerate, that is compound made by 3 atoms of carbon and 1 atom pf phosphorous, among hydrogen atoms.

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Which type of bond is formed with when two Atomic share Park appear ​
Ber [7]

I think it's covalent...? Hope that helps.

3 0
3 years ago
Which of the following equations are correctly balanced
IRINA_888 [86]
Ion know yo but good luck
7 0
3 years ago
Ethane, C2H6, burns in oxygen. First write a balanced equation for this combustion reaction. What mass of oxygen, in grams, is r
iren [92.7K]

Answer:

We need 50.6 grams of oxygen

Explanation:

Step 1: Data given

Mass of ethane = 13.6 grams

Molar mass of ethane = 30.07 g/mol

Step 2: The balanced equation

2C2H6 + 7O2 → 4CO2 + 6H2O

Step 3: Calculate moles ethane

Moles ethane = mass ethane / molar mass ethane

Moles ethane = 13.6 grams / 30.07 g/mol

Moles ethane = 0.452 moles

Step 4: Calculate moles oxygen

For 2 moles ethane we need 7 moles O2 to produce 4 moles CO2 and 6 moles H2O

For 0.452 moles ethane we need 3.5*0.452 = 1.582 moles O2

Step 5: Calculate mass O2

Mass O2 = moles O2 * molar mass O2

Mass O2 = 1.582 moles * 32.0 g/mol

Mass O2 =  50.6 grams

We need 50.6 grams of oxygen

7 0
3 years ago
Can someone help me with this please :)
antoniya [11.8K]

Answer: Hydrochloric acid poses a various health risk

5 0
3 years ago
Manganese sulfate forms a pale pink hydrate with the formula MnSO 4 ⋅ n H 2 O ( s ) . If this hydrate is heated to a high enough
Mama L [17]

Answer:

Value of n in MnSO₄.nH₂O is one.

Explanation:

The n represents the number of moles of water attached to the formula unit manganese sulfate. These moles (n) can be determined by taking the ratio of the moles of anhydrous salt and the moles of water. The moles of water can be determined by taking the difference of final and initial mass of the salt. This difference is equal to the mass of the water, mathematically it can be represented as,

Mass of H₂O = initial mass of the salt (g) - final mass of the salt (g)

Mass of H₂O = 16.260 g - 14.527 g

Mass of H₂O = 1.733 g

moles of H₂O = (1.733 g) ÷ (18.015 g/mole)

moles of H₂O =  0.0962

For the moles of anhydrous salt:

moles of MnSO₄ = mass of MnSO₄ ÷ molar mass of MnSO₄

moles of MnSO₄ = 14.5277 ÷ 151.001

moles of MnSO₄= 0.0962

Now for n:

n = moles of water ÷ moles of MnSO₄

n = 0.0962 ÷ 0.0962

n = 1

The above calculations show that one mole of H₂O is attached to the  one formula unit of MnSO₄

8 0
3 years ago
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