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mihalych1998 [28]
3 years ago
9

What information does the first quantum number of an electron give?

Chemistry
1 answer:
bazaltina [42]3 years ago
4 0

Answer:

с

Explanation:

the first quantum number of an electron gives the information about the energy level the electron is in

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When heated strongly, copper metal incorporates oxygen to form one of the copper oxides from the last problem. In one experiment
Whitepunk [10]

Answer:

1 mol of copper

Explanation:

The mass of the oxide formed is the total mass less the crucible mass, so it is:

100.52 - 88.00 = 12.52 g

It means that 10.00 g is from copper, and 2.52 g is from oxygen. The molar mass of copper is 63.50 g/mol, and the molar mass of oxygen is 16 g/mol. The number of moles (n) is the mass divided by the molar mass:

n Cu = 10.00/63.50 = 0.158 moles

n O = 2.52/16 = 0.158 moles

So, there is the same number of moles of each element, and the product must be: CuO, which has 1 mol of copper.

8 0
3 years ago
The tendency of a moving object to continue moving in a straight line or a stationary object to remain in place is called
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The tendency of a moving object to continue moving in a straight line or a stationary object to remain in place is called inertia.

Answer: C) or the third option.
5 0
3 years ago
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I need help on my 6th grade science:)
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Nucleus. Hope this helps!!
4 0
3 years ago
The weathering of a tall mountain down into a low-lying hill is an example of a landform being changed through a ______ process
e-lub [12.9K]

an erosive process or erosion

erosion is when a rock is changed through the weather

7 0
3 years ago
A piece of charcoal is found to contain
Naddika [18.5K]

Answer: The tree died 9709.46 years before.

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  

t = age of sample

a = let initial amount of the reactant = 100

a - x = amount left after decay process = \frac{30}{100}\times 100=30

a) to find rate constant

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

k=\frac{0.693}{5600years}=1.24\times 10^{-4}years^{-1}

b) to know the age

t=\frac{2.303}{1.24\times 10^{-4}}\log\frac{100}{30}

t=9709.46years

The tree died 9709.46 years before.

8 0
3 years ago
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