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Reil [10]
3 years ago
15

Sodium-24 has a half life how much sodium-24 will remain in an 18 g sample after 75 hours

Chemistry
1 answer:
frutty [35]3 years ago
3 0

Answer:

\boxed{\text{0.56 g}}

Explanation:

The half-life of Na-24 (15 h) is the time it takes for half of it to decay.  

After one half-life, half (50 %) of the original amount will remain.  

After a second half-life, half of that amount (25 %) will remain, and so on.  

We can construct a table as follows:  

  No. of                 Fraction          Mass

<u>half-lives   t/da   Remaining   Remaining/g </u>

      0             0           1                      18

       1            15            ½                    9.0

      2           30            ¼                    4.5

      3           45            ⅛                    2.2

      4           60            ⅟₁₆                   1.1

      5           75            ⅟₃₂                   0.56

      6           90           ⅟₆₄                   0.28

We see that  \boxed{\textbf{0.56 g}} remain after five half-lives (75 h).

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<h3>What is IUPAC?</h3>

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Explanation:

Hello,

In this case, we can analyze the colligative property of solutions - freezing point depression - for the formed solution when ethylene glycol mixes with water. Thus, since water freezes at 0 °C, we can compute the freezing point of the solution as shown below:

T_{sol}=T_{water}-i*m*Kf

Whereas the van't Hoff factor for this solute is 1 as it is nonionizing and the molality is:

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REWRITE THIS IN YOUR OWN WORDS PLEASE, THANK YOU.

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