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WARRIOR [948]
3 years ago
14

Simplify

rac{3}{8} } " alt=" \sqrt{ \frac{3}{8} } " align="absmiddle" class="latex-formula">

Mathematics
1 answer:
Pie3 years ago
3 0

Answer:

B (√6)/4

Step-by-step explanation:

The smallest multiplier that will make the denominator of the fraction into a perfect square is 2, so you have ...

\displaystyle\sqrt{\frac{3}{8}}=\sqrt{\frac{3\cdot 2}{8\cdot 2}}\\\\=\sqrt{\frac{6}{16}}=\frac{\sqrt{6}}{\sqrt{16}}\\\\=\frac{\sqrt{6}}{4}

_____

Answer choice D is also a correct rationalization of the denominator, but is not simplified as far as it can be. √24 = 2√6, so a factor of 2 can be cancelled from numerator and denominator, giving answer choice B.

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In rhombus ABCD, the diagonals AC and BDintersect at E. If AE=5 and BE=12, what is thelength of AB?
hram777 [196]

Diagonals that bisect each other are perpendicular and form a right angle.

AEB is a right triangle.

We can apply the Pythagorean theorem:

c^2 = a^2+b^2

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Replacing:

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8 0
9 months ago
Please apply the properties of rational exponents to simplify expressions with radical or rational exponents. Explain the steps
schepotkina [342]

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6 0
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