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andrezito [222]
3 years ago
12

Simplify the expressions 24/(2*6)+5

Mathematics
2 answers:
barxatty [35]3 years ago
4 0
24/ 12+5
24/17
1.411. Just do whats in parenthesis and then add that to whats left. So just add like terms. and then divide whats left. Use PEMDAS
 Parenthesis exponents multiplication. division addition subtraction
AveGali [126]3 years ago
3 0
7 because 2 times 6 equals 12 divided by 24 equals 2 plus 5 equals 7
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What is the solution to the system of equations below? Y=-1/4x+2 and 3y=-3/4x-6
fgiga [73]

<u>Answer:</u>

There are infinite solutions to the system of equations given

<u>Solution: </u>

The given equations given are,

y=-\frac{x}{4}+2------ (i)

3 y=-\frac{3 x}{4}-6---- (ii)

Now putting the value of (i) in (ii) we get,

3 \times\left(-\frac{x}{4}+2\right)=-\frac{3 x}{4}-6

\Rightarrow-\frac{3 x}{4}+6=-\frac{3 x}{4}-6

\Rightarrow\frac{3 x}{4}-\frac{3 x}{4}=-12

\Rightarrow0 \times x=-12

\Rightarrowx=(\frac{-12}{0})=\infty

So, there are <em>infinite solutions</em> to the system.

4 0
3 years ago
Based on census data, the population of Freedonia is modeled by the function P ( t ) = 325 t^2 + 28547 people, where t represent
navik [9.2K]

Answer:

dP/dt = 650t = 650(2 ) = 1,300 people/year

The rate of increasing of population at the end of the year 1992 is 1,300 people/year

Step-by-step explanation:

Given;

Population function as;

P(t) =325 t^2 + 28547

The rate of change of the population dP/dt at any given time can be given as;

Rate = change in population/change in time = dP/dt

dP/dt = 2×325t = 650t

Therefore, after 1992;

t = 1992-1990 = 2years

dP/dt = 650t = 650(2 ) = 1,300 people/year

The rate of increasing of population at the end of the year 1992 is 1,300 people/year

5 0
4 years ago
How do I figure out the answer to <br> Y=3x-19<br> Y=x+1
iren [92.7K]
You can set them equal to eachother
x+1=3x-19
solve for X
-3x both sides
-2x+1=-19
-1 both sides
-2x=-20
÷-2 both sides
x=10
y=10+1
y=11
8 0
3 years ago
Can someone help with this? You dont really have to solve it (I mean you can if you want to....) But if not, can someone explain
sukhopar [10]

Answer:

43

Step-by-step explanation:

3 0
3 years ago
What are the possible values of x for the following functions? f(x)=2-x/x(x-1)
nevsk [136]

The possible values of x for the following functions are values on real number except 0 and 1

<h3>Domain of a function</h3>

The domain of a function are the values of the independent variable for which it exists.

Given the function below

f(x)=2-x/x(x-1)

The function does not exist at the. point where the denominator is zero. From the function given, the function does not exist when;

x(x -1) = 0

x = 0 and x = 1

Hence the possible values of x for the following functions are values on real number except 0 and 1

Learn more on domain of a function here; brainly.com/question/1770447

#SPJ1

5 0
1 year ago
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