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3 years ago

Hmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

Mathematics

2 answers:

allsm [11]3 years ago

8 0

Answer:

C is the correct answer

Murrr4er [49]3 years ago

8 0

Answer:

A and D

Step-by-step explanation:

If these lines are parallel, which I'm assuming they are, we know that any angles across from each other are equal, because they're <u>vertical angles.</u>

angle 1 = 41

angle 2 = 139

angle 3 = 139

angle 4 = 41

<u>This means that choices A and D are correct!</u>

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3 years ago

Please please help!!

shepuryov [24]

Answer:

$\large\boxed{x=0\ and\ x=\pi}$

Step-by-step explanation:

$\tan^2x\sec^2x+2\sec^2x-\tan^2x=2\\\\\text{Use}\ \tan x=\dfrac{\sin x}{\cos x},\ \sec x=\dfrac{1}{\cos x}:\\\\\left(\dfrac{\sin x}{\cos x}\right)^2\left(\dfrac{1}{\cos x}\right)^2+2\left(\dfrac{1}{\cos x}\right)^2-\left(\dfrac{\sin x}{\cos x}\right)^2=2\\\\\left(\dfrac{\sin^2x}{\cos^2x}\right)\left(\dfrac{1}{\cos^2x}\right)+\dfrac{2}{\cos^2x}-\dfrac{\sin^2x}{\cos^2x}=2$

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$\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{(1+\cos^2x)(\cos^2x)}{(\cos^2x)^2}=2\qquad\text{Use the distributive property}\\\\\dfrac{1-\cos^2x+\cos^2x+\cos^4x}{\cos^4x}=2\\\\\dfrac{1+\cos^4x}{\cos^4x}=2\qquad\text{multiply both sides by}\ \cos^4x\neq0\\\\1+\cos^4x=2\cos^4x\qquad\text{subtract}\ \cos^4x\ \text{from both sides}\\\\1=\cos^4x\iff \cos x=\pm\sqrt1\to\cos x=\pm1\\\\ x=k\pi\ for\ k\in\mathbb{Z}\\\\\text{On the interval}\ 0\leq x$

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Sauron [17]

Corresponding is the answer.

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S.Area=2(lw+wh+lh)
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Surface Area: 2(8)+2(12)+2(24)=16+24+48=88 m²

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3 years ago

Hmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm​

Hmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm