You need to put the x or y value in the other equation ;
For example excersize a
It given that
Y=x^2+3x-1
Then you put it on the first equation :
x+x^2+3x-1=4
And then you solve it
x+x^2+3x-1-4=0
4x+x^2-5=0
We will make the order to seem easier
x^2+4x-5=0
x1=-5
x2=1
Then you put the x1,2 that you found on the second equation :
y=(-5)^2+3*(-5)-1=9
y=1^2+3*1-1=3
For summary :
x1=-5
x2=1
y1=9
y2=3
The answer is C Rectangle
Answer:
yes
Step-by-step explanation:
Each x-value is only listed once, so the relation <em>is a function</em>.
__
A function maps each x-value to only one y-value. If an x-value is listed more than once (with different y-values), then the relation is not a function.
X=number of boys.
y=number of girls.
we suggest this system of equation
x/y=9/7
x=y+116
We solve this system of equation by substitution method.
(y+116)/y=9/7
7(y+116)=9y
7y+812=9y
9y-7y=812
2y=812
y=812/2=406
x=y+116
x=406+116=522
answer: At the school there are 522 boys and 406 girls.
to chek.
522/406=1.2857...
9/7=1.2857...
The number of boys (522) is equal to 406+116=522.
It's going down by five but I'm sure on the last one..but to help add a zero like if it 0.5 it would be 0.50 that should help.
