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3 years ago

Which of the following polygons can form a regular tessellation?

Mathematics

1 answer:

anyanavicka [17]3 years ago

3 0

Answer:

option A.

Step-by-step explanation:

The regular polygons that can be used to form a regular tessellation are an equilateral triangle, a square, and a regular hexagon.

HOPE THIS HELPS.

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Simplify completely 3x+18/18

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Answer:

X-6/6 is your answer.

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3 years ago

stephanie rides her bike 2 miles to the post office and then another 50 yards to the train station . How many yards long was her

kherson [118]

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4 years ago

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What are relatively prime numbers?

Helga [31]

Answer:

When two numbers have no common factors other than 1. In other words there is no value that you could divide them both by exactly (without any remainder).

Step-by-step explanation:

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3 years ago

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Solve for K: 40 + K = 56 K=

leva [86]

Answer:

k=16

Step-by-step explanation:

To solve this, we can isolate k.

40+k=56.

We can do this by subracting 40 from both sides.

40+k-40=k

56-40=16

k=16

4 0

3 years ago

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each afternoon maria walks the dogs at a local pet shelter for up to 2 hours. maria spends 16 minutes walking a large dog and 12

jonny [76]

$16x + 12y\leq 120$ is the inequality that represents this situation

The greatest number of large dogs that she could have walked that afternoon is 3

Solution:

Each afternoon maria walks the dogs at a local pet shelter for up to 2 hours

Maria spends 16 minutes walking a large dog and 12 minutes walking a small dog

To find: Inequality for this situation

Let "x" be the number of large dogs taken for walking

Let "y" be the number of small dogs taken for walking

Total time spend = 2 hours = 120 minutes

Time spent for large dog = 16 minutes

Time spent for small dog = 12 minutes

Therefore, a inequality is framed as:

number of large dog x Time spent for large dog + number of small dogs x Time spent for small dog $\leq$ Total time spend

$x \times 16 + y \times 12\leq 120\\\\16x + 12y\leq 120$

Here we used "less than or equal to" , since total time spend is up to 2 hours

Thus the inequality is found

If maria walked 9 dogs in one afternoon, what is the greatest number of large dogs that she could have walked that afternoon?

So total dogs = 9

number of large dogs + number of small dogs = 9

x + y = 9

y = 9 - x --- eqn 1

Substitute eqn 1 into inequality

$16x + 12(9-x)\leq 120\\\\16x + 108-12x\leq 120\\\\4x\leq 12\\\\x\leq 3$

Thus the greatest number of large dogs that she could have walked that afternoon is 3

5 0

3 years ago