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Ad libitum [116K]
3 years ago
9

7/10 is blank pieces of the whole

Mathematics
1 answer:
solniwko [45]3 years ago
5 0
7/10 is 7 pieces of the whole. The whole would be cut into 10 pieces and you have 7 of the 10...7/10.
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Harry took a loan from the bank.
inna [77]

Answer:

If there is no interest then $9000

Step-by-step explanation:

-200t represents paying back 200 dollars a month

9000 represents original debt (including interest)

3 0
3 years ago
Factor -y - 8.<br> Please hurry it’s timed
max2010maxim [7]

Answer:

need more info

Step-by-step explanation:

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3 years ago
What are the apparent zeros of the cubic function graphed above? (also if you have the answers to the rest of this test plz send
Mazyrski [523]

<em>The point where a function (for our problem its the cubic function shown)</em>

  • cuts/crosses the x-axis

<u>and/or</u>

  • touches the x-axis

<em>is a zero of the function.</em>

From the graph shown, we can clearly see that it cuts the x-axis at -1 and touches the x-axis at 2.

So the zeros are at -1 and 2.


ANSWER: {-1,2}


7 0
3 years ago
Read 2 more answers
Find the area of the shaded circle.give your answer in 3 significant numbers​
DENIUS [597]

Answer:

116 cm²

Step-by-step explanation:

The area of a circle = πr² ← r is the radius

shaded area = external area - internal area

                      = π × 6.5² - π × 2.3²

                      = π( 42.25 - 5.29)

                      = π × 36.96 ≈ 116 cm²

4 0
3 years ago
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A triangle has side lengths of 9 in, 13 in, and 20 in. What is the measurement of this triangle's largest angle?
Rama09 [41]

1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :

     i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.

      ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:

       a^{2}=b ^{2}+c ^{2}-2bc(cosA)

2.

20^{2}=9 ^{2}+13 ^{2}-2*9*13(cosA)&#10;&#10;400=81+169-234(cosA)   150=-234(cosA)&#10;&#10;cosA=150/-234= -0.641

3. m(A) = Arccos(-0.641)≈130°,

4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc

6 0
3 years ago
Read 2 more answers
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