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3 years ago

What is the domain and range of the relation shown in the table?

Mathematics

2 answers:

marin [14]3 years ago

7 0

The domain is all ur x values and the range is all ur y values

so ur domain is { 10,15,19,32 } and ur range is { -1,5,9 }....and if ur numbers repeat, u only have to write them once

lubasha [3.4K]3 years ago

4 0

THat would be the third choice.

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How do u simplify each expression by combining like terms?

Masja [62]

Answer:

1. 8y - 9y = -1y

( 8 - 9 = -1)

3. 8a - 6 +a - 1

( i have showed the like terms here)

8a - 1a= 7a

-6 - 1 = -7

7a - 7

5. -x - 2 + 15x

( i have showed the like terms here)

-x + 15x = 14x

(x = 1)

14x + 2

7. 8d - 4 - d - 2

( i have showed the like terms here)

8d - d = 7d

-4 -2 = -6

7d - 6

8. 9a + 8 - 2a - 3 - 5a

( i have showed the like terms here)

9a - 2a - 5a = 2a

8 - 3= 5

2a + 5

6 0

3 years ago

The scientific notation 2 x 10^-2 has what value?

PIT_PIT [208]

The value is 0.02

If it is a negative number, you move the decimal over to the left. :)

8 0

3 years ago

Pls help I have no idea what I’m doing

olganol [36]

Answer:

1800

Step-by-step explanation:

61 around to 60 and 29 rounds to 30. so

60 ×30=1800

8 0

3 years ago

The area of a rectangle is 30+12x what are 3 possibilities for the length and width of the rectangle

Stolb23 [73]

In order to find the three possibilities, you must first think of common factors between 30 and 12:

Factors of 30: 1, 2, 3, 5, 6, 10, 15, 30

Factors of 12: 1, 2, 3, 4, 6, 12

We can find three common factors between the two numbers: 2, 3, and 6. So these are three widths that we can use. The length can be found by factoring out the numbers from 30+12x (we can't factor out x):

30+12x=2(15+6x) Width: 2 Length: 15+6x

20+12x=3(10+4x) Width: 3 Length: 10+4x

20+12x=6(5+2x) Width: 6 Length: 5+2x

4 0

3 years ago

List of subsets of each set {1,3,5,7}

agasfer [191]

ANSWER

{},{1},{3},{5},{7},{1,3},{1,5},{1,7},{3,5},{3,7},{5,7},{1,3,5},{1,3,7},{3,5,7},{1,5,7},{1,3,5,7}

EXPLANATION

The given set is {1,3,5,7}.

This set has

${2}^{n} = {2}^{4} = 16$

subsets.

Where n=4 is the number of elements in the set.

Recall that the null set is a subset of every set and every set is a subset of itself.

The subsets are:

{}

{1},{3},{5},{7}

{1,3},{1,5},{1,7},{3,5},{3,7},{5,7}

{1,3,5},{1,3,7},{3,5,7},{1,5,7}

{1,3,5,7}

7 0

3 years ago