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zhannawk [14.2K]
3 years ago
13

What is the domain and range of the relation shown in the table?

Mathematics
2 answers:
marin [14]3 years ago
7 0
The domain is all ur x values and the range is all ur y values

so ur domain is { 10,15,19,32 } and ur range is { -1,5,9 }....and if ur numbers repeat, u only have to write them once
lubasha [3.4K]3 years ago
4 0
THat would be the third choice.
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The rock hits the gorund at 45s. is the answer
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3 years ago
Which number line represents the solution set for the inequality - 글 x 2 47
aleksandr82 [10.1K]

Answer:

dufenschmertz evil incorporated...

Step-by-step explanation:

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7 0
3 years ago
Find three consecutive even numbers whose sum is 1674.
Norma-Jean [14]

Answer:

556, 558, and 560

Step-by-step explanation:

1674/3 = 558 (An even number, yay)

So 558 + 558 + 558 = 1674

Subtract two from the first one and add two to the last (still equal)

556 + 558 + 560

adding them equals 1674 so the answer is

556, 558, and 560

7 0
3 years ago
You ask a friend to think of a number feom two to twelve. What is the probability that his numberwill ne 4?
antiseptic1488 [7]
The probability that his number will be 4 is one in eleven, or 1/11.
4 0
3 years ago
Read 2 more answers
The probability density function of the time to failure of an electronic component in a copier (in hours) is f(x) for Determine
salantis [7]

The question is incomplete. Here is the complete question.

The probability density function of the time to failure of an electronic component in a copier (in hours) is

                                              f(x)=\frac{e^{\frac{-x}{1000} }}{1000}

for x > 0. Determine the probability that

a. A component lasts more than 3000 hours before failure.

b. A componenet fails in the interval from 1000 to 2000 hours.

c. A component fails before 1000 hours.

d. Determine the number of hours at which 10% of all components have failed.

Answer: a. P(x>3000) = 0.5

              b. P(1000<x<2000) = 0.2325

              c. P(x<1000) = 0.6321

              d. 105.4 hours

Step-by-step explanation: <em>Probability Density Function</em> is a function defining the probability of an outcome for a discrete random variable and is mathematically defined as the derivative of the distribution function.

So, probability function is given by:

P(a<x<b) = \int\limits^b_a {P(x)} \, dx

Then, for the electronic component, probability will be:

P(a<x<b) = \int\limits^b_a {\frac{e^{\frac{-x}{1000} }}{1000} } \, dx

P(a<x<b) = \frac{1000}{1000}.e^{\frac{-x}{1000} }

P(a<x<b) = e^{\frac{-b}{1000} }-e^\frac{-a}{1000}

a. For a component to last more than 3000 hours:

P(3000<x<∞) = e^{\frac{-3000}{1000} }-e^\frac{-a}{1000}

Exponential equation to the infinity tends to zero, so:

P(3000<x<∞) = e^{-3}

P(3000<x<∞) = 0.05

There is a probability of 5% of a component to last more than 3000 hours.

b. Probability between 1000 and 2000 hours:

P(1000<x<2000) = e^{\frac{-2000}{1000} }-e^\frac{-1000}{1000}

P(1000<x<2000) = e^{-2}-e^{-1}

P(1000<x<2000) = 0.2325

There is a probability of 23.25% of failure in that interval.

c. Probability of failing between 0 and 1000 hours:

P(0<x<1000) = e^{\frac{-1000}{1000} }-e^\frac{-0}{1000}

P(0<x<1000) = e^{-1}-1

P(0<x<1000) = 0.6321

There is a probability of 63.21% of failing before 1000 hours.

d. P(x) = e^{\frac{-b}{1000} }-e^\frac{-a}{1000}

0.1 = 1-e^\frac{-x}{1000}

-e^{\frac{-x}{1000} }=-0.9

{\frac{-x}{1000} }=ln0.9

-x = -1000.ln(0.9)

x = 105.4

10% of the components will have failed at 105.4 hours.

5 0
3 years ago
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