2/3 of a pizza is more than half of the pizza.
3/6 = 1/2, so 3/6 of a pizza is exactly half of the pizza.
Given that two pizzas are of different sizes you need to calculate the areas of each pizza and compare them.
Assumming that the two pizzas are circular, you can calculate the area of each pizza from the formula of the area for a circle:
Area of a circle = π * (radius)^2.
Call r the radius of Jake's pizza and R the radius of Al's pizza. Then:
Area of Jake's pizza = π (r^2) and 2/3 of that is: 2π(r^2) / 3.
Area of Al's pizza = π (R^2) and 1/2 of that is π(R^2)/2
So, what you have to do is to use the radius of each pizza, calculate above formulaes and verify whether the results are the same or not.
Hello there! The formula for dividing fraction is keep, change, flip. You keep the first fraction the same, change division into multiplication, and flip the second fraction over by its reciprocal. In this case, 5/12 remains the same, division becoems multiplication, and 20/36 flips over to become 36/20. So the expression becomes this:
5/12 * 36/20
Now, we multiply straight across. 5 * 36 is 180. 12 * 20 is 240. 180/240 is 3/4 in simplest form. There. The quotient is 3/4.
Answer:
B 204 bc 34x6 =204
Step-by-step explanation:
Answer: Annie has 49 Quarters
Explanation:
Sarah has 21 more quarters than Annie.
As shown, It says That Sarah has 28 quarters.
So, if Sarah has 21 more, it means you add 21 + 28
Resulting in 49.
Hope this helps you! If available please give me a Branliest. It is much appreciated!
- Mathhotdog •~•
Answer:
On occasions you will come across two or more unknown quantities, and two or more equations
relating them. These are called simultaneous equations and when asked to solve them you
must find values of the unknowns which satisfy all the given equations at the same time.
Step-by-step explanation:
1. The solution of a pair of simultaneous equations
The solution of the pair of simultaneous equations
3x + 2y = 36, and 5x + 4y = 64
is x = 8 and y = 6. This is easily verified by substituting these values into the left-hand sides
to obtain the values on the right. So x = 8, y = 6 satisfy the simultaneous equations.
2. Solving a pair of simultaneous equations
There are many ways of solving simultaneous equations. Perhaps the simplest way is elimination. This is a process which involves removing or eliminating one of the unknowns to leave a
single equation which involves the other unknown. The method is best illustrated by example.
Example
Solve the simultaneous equations 3x + 2y = 36 (1)
5x + 4y = 64 (2) .
Solution
Notice that if we multiply both sides of the first equation by 2 we obtain an equivalent equation
6x + 4y = 72 (3)
Now, if equation (2) is subtracted from equation (3) the terms involving y will be eliminated:
6x + 4y = 72 − (3)
5x + 4y = 64 (2)
x + 0y = 8
