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3 years ago

Unit Test

Mathematics

1 answer:

natima [27]3 years ago

3 0

Answer:

The density approaches infinity.

Step-by-step explanation:

dont need explanation

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PLEASE HELP ME WITH THIS QUESTION!!! WHATS THE ANSWER?? I WILL GIVE YOU BRAINLIEST AND A THANKS!!! THANK YOUUU!!! <33

Free_Kalibri [48]

Answer:

A) 113 m²

Step-by-step explanation:

Use the formula for area of a circle.

Area of a circle = πr²

π = pi = 3.14 (rounded)

r = radius

² = the power of 2, or the radius (in this case) multiplied by itself.

Note that the radius is given, and it is 6. Plug in 6 for the radius:

A (circle) = π(6)²

First, solve the power. Multiply 6²:

6² = 6 * 6 = 36

Next, multiply 36 with π (3.14):

36 x 3.14 = 113.04

A) 113 m² is your closest answer.

6 0

2 years ago

Read 2 more answers

X + 5 = 24 whar values can be substituted for x to make the equation true

levacccp [35]

Answer:

x=19

Step-by-step explanation:

24-5=19

8 0

2 years ago

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The points on the graph of the function y=3+f(x-1) can be obtained from the points on y=f(x) by a shift of:

MaRussiya [10]

Answer: 1 to the right and 3 up

4 0

2 years ago

√12 + √10 − √2) is

r-ruslan [8.4K]

Hello!

$\bf \sqrt{12} + \sqrt{10} - \sqrt{2} =$

$\bf \sqrt{ {2}^{2} \times 3} + \sqrt{10} - \sqrt{2} =$

$\bf \sqrt{ {2}^{2} } \sqrt{ 3} + \sqrt{10} - \sqrt{2} =$

$\bf \boxed{ 2 \sqrt{3} + \sqrt{10} - \sqrt{2}}$

Answer: (c) An irrational number

Good luck! :)

5 0

2 years ago

I need help <br> Please help ASAP

soldi70 [24.7K]

Answer:

The volume of the solid is $1,021m^3$

Step-by-step explanation:

1. Cylinder

For find the volume of a cylinder we use the next formula:

$V_{cylinder} = \pi h r^2 = \pi \cdot 9m\cdot (5m)^2 \approx 706.86m^3$

Then the volume of the cylinder is equal to $706.86m^3$

2. Cones

For find the volume of a cone we use the next formula:

$V_{cone} = \pi \frac{h}{3} r^2 = \pi \cdot \frac{6m}{3} \cdot (5m)^2 \approx 157.08m^3$

However there are two cones so we have to multiply the volume of one cone for two and we get the total volume for the cones which is $314.16m^3$

3. Sum of the volumes

Finally we sum the volumes of the cylinder and the cones for get the final result

$V_{cylinder} + V_{cones} = 706.86m^3 + 314.16m^3 \approx 1021m^3$

So approximating the result is $1021m^3$

5 0

2 years ago