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MA_775_DIABLO [31]
3 years ago
7

Help me please and sorry about the points it doesn’t let me do more than that

Mathematics
1 answer:
kkurt [141]3 years ago
8 0
I think the slope would be 1.5
explanation: i’m not sure but rise/run,
y2-y1/x2-x1
(1,1.5) (4,6)
6-1.5/4-1=4.5/3=1.5
You might be interested in
Help! Urgent request
TiliK225 [7]

Answer: 6 students

What we know:

Students: 24

Students who play checkers: \frac{2}{3}

Students who also play sudoku:\frac{3}{8} of the \frac{2}{3}

24 ÷ 3 = 8, so 8 × 2 = 16 (students who play checkers)

\frac{3}{8} × 2 = \frac{6}{16}

So the answer is,

6 students play both checkers and sudoku

8 0
3 years ago
Read 2 more answers
A/45 = 5/7 Solve for a
Charra [1.4K]

Answer:

a=225/7

a=32 1/7

a=32.14285714...

5 0
2 years ago
Read 2 more answers
Dos cuadrados de lado
Kaylis [27]

La franja amarilla del rectángulo tiene un área de 30 centímetros cuadrados.

<h3>¿Cuál es el área de la franja amarilla del rectángulo?</h3>

En este problema tenemos un rectángulo formado por dos cuadrados que se traslapan uno al otro. La franja amarilla es el área en la que los cuadrados se traslapan. La anchura del rectángulo es descrita por la siguiente ecuación:

(10 - x) + 2 · x = 17

Donde x se mide en centímetros.

A continuación, despejamos x en la ecuación descrita:

10 + x = 17

x = 7

Ahora, el área de la franja amarilla se determina mediante la fórmula de area de un rectángulo:

A = b · h

Donde:

  • b - Base del rectángulo, en centímetros.
  • h - Altura del rectángulo, en centímetros.
  • A - Área del rectángulo, en centímetros cuadrados.

A = (10 - 7) · 10

A = 3 · 10

A = 30

El área de la franja amarilla del rectángulo es igual a 30 centímetros cuadrados.

Para aprender más sobre áreas de rectángulos: brainly.com/question/23058403

#SPJ1

8 0
11 months ago
The number in front of the decimal point represents part of a unit while the
posledela

Answer:

False

Step-by-step explanation:

Because the numbers before the decimal is the whole number and the ones after arn't

6 0
2 years ago
at the beginning of the school year Anderson Middle School had 480 students at the end of the year it had 504 students what is t
NikAS [45]

Answer:

The number of enrollments increased by 5%.

Step-by-step explanation:

Given that:

Number of students at the beginning of the year = 480

Number of students at the end of the year = 504

Change = 504 - 480 = 24

This indicates increase.

Percent of change = \frac{Change}{Old\ number\ of\ students}*100

Percent of change = \frac{24}{480}*100

Percent of change = 5%

Hence,

The number of enrollments increased by 5%.

4 0
2 years ago
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