Number of tacos sold is 65 and number of burritos sold is 40
<h3><u>Solution:</u></h3>
Given that Aiden sells each taco for $4.75 and each burrito for $7
Let the number of tacos sold be "t" and number of burritos sold be "b"
Given that Aiden sold 25 more tacos than burritos
t = b + 25 ---- eqn 1
Also given that yesterday Aiden made a total of $588.75 in revenue
number of tacos sold x cost of each tacos + number of burritos sold x cost of each burritos = 588.75
4.75t + 7b = 588.75 ----- eqn 2
Substitute eqn 1 in eqn 2
4.75(b + 25) + 7b = 588.75
4.75b + 118.75 + 7b = 588.75
11.75b = 470
b = 40
Substitute b = 40 in eqn 1
t = 40 + 25
t = 65
Thus the number of tacos sold is 65 and number of burritos sold is 40
Answer:
36
Step-by-step explanation:
The initial term is the very first term
36, 24, 16, ...?
has an initial term of 36
X^2-3x = x(x-3)
x^2-9 = x^2 - 3^2 = (x-3)(x+3)
HCF = x-3