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natka813 [3]
3 years ago
13

Suppose a group consists of 5 students. Three students are selected at random to do a presentation. How many different sets of p

resenters are possible?
Computers and Technology
1 answer:
Klio2033 [76]3 years ago
6 0

Answer:

The number of presentation groups of 3 students that can be selected from a group of 5 students equals 10.

Explanation:

The number of different presenters equals the no of possible combinations of 3 students from a pool of 5 students.

Thus the number of possible combinations equals

\binom{5}{3}=\frac{5!}{(5-3)!\times 3!}=10

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Answer:

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void multiplyNumbers (int x, int y,int &product) {

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Explanation:

Declare the method prototype using

void multiplyNumbers(int x, int y,int &product);

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The method is as follows; the & written in front of product implies that product is passed by reference

void multiplyNumbers (int x, int y,int &product) {

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<em>See attachment for complete program</em>

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3 years ago
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