Question

Suppose a group consists of 5 students. Three students are selected at random to do a presentation. How many different sets of presenters are possible?

Answer 1

Answer:

The number of presentation groups of 3 students that can be selected from a group of 5 students equals 10.

Explanation:

The number of different presenters equals the no of possible combinations of 3 students from a pool of 5 students.

Thus the number of possible combinations equals

$\binom{5}{3}=\frac{5!}{(5-3)!\times 3!}=10$