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Yakvenalex [24]
3 years ago
8

O is the centre of the circle, determine the value of v ​

Mathematics
1 answer:
never [62]3 years ago
8 0

Answer:

the angle v =59 degree

..

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In the figure, AB is parallel to CD, XY is the perpendicular bisector of AB, and E is the midpoint of XY. Prove that △AEB ≅ △DEC
Makovka662 [10]

Answer:

From top to bottom:

A, J, E, B, I, C, D, G, F, H

See below for more clarification.

Step-by-step explanation:

We are given that AB is parallel to CD, XY is the perpendicular bisector of AB, and E is the midpoint of XY. And we want to prove that ΔAEB ≅ ΔDEC.

Statements:

1) XY is perpendicular to AB.

Definition of perpendicular bisector.

2) XY ⊥ CD.

In a plane, if a transveral is perpendicular to one of the two parallel lines, then it is perpendicular to the other.

3) m∠AXE = 90°, m∠DYE = 90°.

Definition of perpendicular lines.

4) ∠AXE ≅ ∠DYE.

Right angles are congruent.

5) XE ≅ YE

Definition of a midpoint.

6) ∠A ≅ ∠D.

Alternate Interior Angles Theorem

7) ΔAEX ≅ ΔDEY

AAS Triangle Congruence*

(*∠A ≅ ∠D, ∠AXE ≅ ∠DYE, and XE ≅ YE)

8) AE ≅ DE

Corresponding parts of congruent triangles are congruent (CPCTC).

9) ∠AEB ≅ ∠DEC

Vertical Angles Theorem

10) ΔAEB ≅ ΔDEC

ASA Triangle Congruence**

(**∠A ≅ ∠D, AE ≅ DE, and ∠AEB ≅ ∠DEC)

3 0
3 years ago
Anyone good at math? will give brainlest to correct
V125BC [204]

Answer:

8%

Step-by-step explanation:

27 - 25 = 2

2/25 x 100 = 8%

8% increase

answer is 8%

6 0
3 years ago
Read 2 more answers
(9, 2) and (3,-5). <br> find the distance between the points
adell [148]

Answer:

Is the slopes your doing

Step-by-step explanation:

6 0
3 years ago
Please help me I don’t understand!!!
horrorfan [7]

Answer:

AGAIN DONT FORGET THE X

it would be "y=-4/5x+3"

Step-by-step explanation:

4 0
3 years ago
You're a manager in a company that produces rocket ships. Machine A and Machine B both produce cockpits and propulsion systems.
GalinKa [24]

Answer:

No you cannot.

Step-by-step explanation:

Let c be the amount of time it takes each machine to make 1 cockpit, and p be the amount of time it takes each machine to make 1 propulsion system.

For Machine A, we have 4 cockpits; this would take 4c time.  We also have 6 propulsion systems; this would take 6p time.  Together it takes 26 hours; this would give us

4c+6p=26.

For Machine B, we have 8 cockpits; this would take 8c time.  We also have 12 propulsion systems; this would take 12p time.  Together it takes 56 hours; this would give us

8c+12p=56

This gives us the system

\left \{ {{4c+6p=26} \atop {8c+12p=56}} \right.

To solve this, we want the coefficients of one of the variables to be the same.  To make the coefficients of c the same, we can multiply the top equation by 2:

\left \{ {{2(4c+6p=26)} \atop {8c+12p=56}} \right. \\\\\left \{ {{8c+12p=52} \atop {8c+12p=56}} \right.

To cancel c, we will subtract the second equation from the first one.  However, this also cancels p:

\left \{ {{8c+12p=52} \atop {-(8c+12p=56)}} \right. \\\\0+0=-4\\0=-4

We get a statement that is not true; thus the system has no solution, and we cannot solve for a unique amount of time.

7 0
3 years ago
Read 2 more answers
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