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3 years ago

Solve for the expression (k+m) Detailed steps would be great, thx

Mathematics

1 answer:

lesya [120]3 years ago

3 0

Answer:

idturursurzrxixtiti yyfffdruh

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Please help thanks!!!

lora16 [44]

$probablity \: of \: \: six = 29 : 150$

<h2>hope it helps you ❣❣ </h2>

<h2>Mark me as brainliest</h2>

in fraction=29/150

3 0

3 years ago

Write the equation in the form Ax + By = C. Find an equation of a line passing through the pair of points (-7,3) and (-8,-9).

Illusion [34]

Answer:

12x -y = -87

Step-by-step explanation:

You can start with the 2-point form of the equation of a line and manipulate it to give you the standard form.

y = (y2 -y1)/(x2 -x1)(x -x1) +y1

y = (-9 -3)/(-8 -(-7))(x -(-7)) +3

y = (-12/-1)(x +7) +3

y = 12x +84 +3

-12x +y = 87 . . . . . subtract the x-term

12x -y = -87 . . . . . . make the leading coefficient positive (per standard form)

3 0

3 years ago

Factor the quadratic equation below to reveal the solutions. X^2+4x-21=-9

a_sh-v [17]

Answer:

x = 3 and x = -7

Step-by-step explanation:

The given quadratic equation is $x^2+4x-21=0$ . We need to find the solution of this equation.

If the equation is in the form of $ax^2+bx+c=0$ , then its solutions are given by :

$x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

Here, a = 1, b = 4 and c = -21

Plugging all the values in the value of x, such that :

$x=\dfrac{-b+ \sqrt{b^2-4ac} }{2a},\dfrac{-b- \sqrt{b^2-4ac} }{2a}\\\\x=\dfrac{-4+ \sqrt{(4)^2-4\times 1\times (-21)} }{2(1)},\dfrac{-4- \sqrt{(4)^2-4\times 1\times (-21)} }{2(1)}\\\\x=3, -7$

So, the solutions of the quadratic equation are 3 and -7.

6 0

3 years ago

4 pairs of pants for 22.60. what is the unit rate?

Alona [7]

Answer:

$5.65

Step-by-step explanation:

Divide 22.6 / 4.

5.65

Best of Luck!

8 0

3 years ago

Law of cosines.Anyone good in Trigonometry?

marin [14]

Answer:

$c=11.8\ units$

Step-by-step explanation:

we know that

The formula of law of cosines is equal to

$c^2=a^2+b^2-2(a)(b)cos(C)$

where

a, b and c are sides. C is the angle opposite side c

In this problem we have

$a=3\ units\\b=10\ units$

$C=120^o$

substitute the given values

$c^2=3^2+10^2-2(3)(10)cos(120^o)$

$c^2=109-(60)cos(120^o)$

$c^2=109-(60)(-0.5))$

$c^2=109+30$

$c^2=139$

$c=11.8\ units$

3 0

3 years ago