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3 years ago

14

Can you please help me solve this ,whats p+4 < -24 ???

1 answer:

Sindrei [870]3 years ago

6 0

P + 4 < -24
p + 4 - 4 < -24 - 4
p < -28

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A rectangle with sides 12 cm and 14 cm has the same diagonal as a square.

umka2103 [35]

Answer:

$a=\sqrt{170}$

Step-by-step explanation:

<u>Diagonal of a Square</u>

Given a square of length side a, the length of the diagonal is

$D=\sqrt{2}a$

The diagonal of a rectangle of sides x and y is

$D=\sqrt{x^2+y^2}$

The sides have lengths 12 cm and 14 cm, the diagonal is

$D=\sqrt{12^2+14^2}$

$D=\sqrt{340}$

Since this value is the same of the diagonal of certain square, we can say

$\sqrt{2}a=\sqrt{340}$

Dividing by $\sqrt{2}$

$\boxed{a=\sqrt{170}}$

6 0

3 years ago

This is due like right now, please help me!!!!

Varvara68 [4.7K]

$\bold{\huge{\orange{\underline{ Solution }}}}$

$\bold{\underline{ Given \: Rules}}$

<u>The </u><u>sum</u><u> </u><u>of </u><u>the </u><u>number </u><u>in </u><u>each </u><u>of </u><u>the </u><u>four </u><u>rows </u><u>is </u><u>the </u><u>same </u>
<u>The </u><u>sum </u><u>of </u><u>the </u><u>numbers </u><u>in </u><u>each </u><u>of </u><u>the </u><u>three </u><u>columns </u><u>is </u><u>the </u><u>same</u>
<u>The </u><u>sum </u><u>of </u><u>any </u><u>row </u><u>does </u><u>not </u><u>equal </u><u>the </u><u>sum </u><u>of </u><u>any </u><u>column </u>

$\bold{\underline{ Let's \: Begin}}$

<u>According </u><u>to </u><u>the </u><u>Second</u><u> </u><u>rule </u><u>:</u><u>-</u>

$\sf{ 75+b+83=76+80+d=a+81+85+78+c+e }$

$\sf{ 158 + b = 156 + d = 166 + a = 78 + c + e ...(1)}$

<u>According </u><u>to </u><u>the </u><u>first </u><u>rule </u><u>:</u><u>-</u><u> </u>

$\sf{ 75+76+a+78 = b+80+81+c = 83+86+d+e}$

$\sf{ 229 + a = 161 + b + c = 168 + d + e ...(2)}$

<u>From </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u> </u><u>we </u><u>got </u><u>:</u><u>-</u>

$\sf{ 158 + b = 166 + a, 156 + d = 166 + a }$

$\sf{ b = 166 - 158 + a, d = 166 - 156 + a }$

$\sf{ b = 8 + a, d = 10 + a ...(3)}$

<u>Subsitute </u><u>(</u><u>3</u><u>)</u><u> </u><u>in </u><u>(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>:</u><u>-</u>

$\sf{229+a = 161+8+a+c = 168+10+a+e}$

$\sf{ 229+a = 169+a+c = 178+a+e}$

<u>We</u><u> </u><u>can </u><u>write </u><u>it </u><u>as </u><u>:</u><u>-</u>

$\sf{ 229+a = 169+a+c \:or\:229+a = 178+a+e}$

$\sf{ c = 299-169+a-a\:or\:e = 229-178+a-a}$

$\sf{ c = 60 \: and \: e = 51 }$

<u>Subsitute </u><u>the </u><u>value </u><u>of </u><u>c </u><u>and </u><u>e </u><u>in </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u><u>-</u>

$\sf{ 158 + b = 156 + d = 166 + a = 78 + 60 + 51 }$

$\sf{ 158 + b = 156 + d = 166 + a = 189}$

<u>Now</u><u>, </u>

$\sf{ For \: b, 158 + b = 189 }$

$\sf{ b = 189 - 158 }$

$\sf{ b = 31}$

$\sf{ For \: d , 156 + b = 189 }$

$\sf{ d = 189 - 156 }$

$\sf{ d = 33}$

$\sf{ For \: a, 166 + a = 189 }$

$\sf{ a = 189 - 166 }$

$\sf{ a = 23 }$

Hence, The value of a, b, c, d and e is 23, 31 ,60 ,33 and 51 .

8 0

3 years ago

9 over 6 as a percent

stiv31 [10]

150%. since you already have 6, that's 100%. the extra 3 is half of the 6, meaning that it would be 50%

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3 years ago

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Derive the equation of the parabola with a focus at (0, 1) and a directrix of y = −1.

mihalych1998 [28]

Ok, so from previous question
(x-h)^2=4p(y-k)

distance from focus to directix is 2
2/2=1=p
1>-1
focus is above the vertex
1 unit down from (0,1) is (0,0)
vertex at (0,0)
since focus is above, p is positive

(x-0)^2=4(1)(y-0)
x^2=4y
4y=x^2
divide both sides by 4
y=(1/4)x^2
f(x)=1/4x^2

2nd one is answer

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3 years ago

One lap around the school track is equivalent to 1/4 of a mile Sandy Ran nine Lap‘s this morning what is the distance she ran in

Debora [2.8K]

Answer:

The answer is 2 and 1/4.

Step-by-step explanation:

You have to do 9 x 1/4 and then you get 2 & 1/4

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4 years ago

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