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goldfiish [28.3K]
3 years ago
8

How many ways are there of seating six people at a round table so that two specific people sit together?

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
5 0

Answer:

6 People in a round table can be seated in (6 - 1) ! ways = 120. Now we need to subtract the number of cases when one of those is sitting next to 2 of the other 5. We can consider as if 5 people are sitting in a row because it is round table.

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Angle A and Angle B are supplementary. Angle A has a measure of 3x - 6 and Angle B has a measure of 54. What is the value of x?
Anni [7]

Answer:

44 degrees

Step-by-step explanation:

Since they are supplementary, they add up to 180. This means that

3x - 6 + 54 = 180

Solving,

3x + 48 = 180

subtract 48 from both sides

3x = 132

divide both sides by 3

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A distributor needs to mix some Terraza coffee that normally sells for $9.00 per pound with some Kona coffee that normally sells
Scrat [10]

Answer:

Step-by-step explanation:

Mixture problems are really easy because the table never varies from one problem to another and they don't have a lot of variations in them like motion problems do. The table for us will look like this, using T for Terraza coffee and K for Kona:

                #lbs     x       $/lb       =         Total

T

K

Mix

Now we just have to fill this table in using the info given. We are told that T coffee is $9 per pound, and that K coffee is $13.50 per pound, so we will fill that in first:

                 #lbs        x        $/lb       =        Total

T                                           9

K                                         13.50

Mix

Next we are told that the mix is to be 50 pounds that will sell for $9.54 per pound

                  #lbs      x       $/lb        =        Total

T                                         9

K                                       13.50

Mix              50                 9.54

Now the last thing we have to have to fill in this table is what goes in the first column in rows 1 and 2. If we need a mix of 50 pounds of both coffees and we don't know how many pounds of each to use, then under T we have x and under K we have 50 - x. Notice along the top we have that the method to use to solve this problem is to multiply the #lbs by the cost per pound, and that is equal to the Total. So we'll do that too:

                 #lbs       x       $/lb      =      Total

T                   x        x          9         =        9x

K             50 - x      x       13.50     =    675 - 13.50x

Mix            50        x         9.54     =     477

The last column is the one we focus on. We add the total of T to the total of K and set it equal to the total Mix:

9x + 675 - 13.5x = 477 and

-4.5x = -198 so

x = 44 pounds. This means that the distributor needs to mix 44 pounds of T coffee with 6 pounds of K coffee to get the mix he wants and to sell that mix for $9.54 per pound.

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3 years ago
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cricket20 [7]

try it on                    

https://www.wolframalpha.com it will helpp you for the math problem :)

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The correct answer is C. 6(x-4)
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2 years ago
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