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puteri [66]
3 years ago
15

Austin is serving his child french fries and chicken wings for lunch today. Let be the number of french fries in the lunch, and

let be the number of chicken wings. Each french fry has calories, and each chicken wing has calories. Austin wants the total calorie count from the french fries and chicken wings to be less than calories. Using the values and variables given, write an inequality describing this.
Mathematics
1 answer:
seropon [69]3 years ago
5 0

Answer:

25f+100c<500

Step-by-step explanation:

He wants that total calorie count to be less than 500 cals, so we use <.

25f, means for each french fries we have 25 calrs.

100c, for each chicken wings we have 100 calories.

So inequality is 25f+100c<500.

For example, he can not eat 4 french fries and 4 wings (4*25+100*4=500 is not less from 500, it is equal), but he can eat 3 fries and 4 wings (3*25+100*4=475<500).

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11.1.30<br> How many three-digit even numbers are possible if the leftmost digit cannot be zero?
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The total number of 3 digit even numbers is 450

Step-by-step explanation:

Step 1 :

We need to determine the  number of 3 digit numbers which is even and the leftmost digit is not zero .

The  3 digits with left most digit not equal to zero starts from 100 and goes up to 998

If we consider only the even 3 digit numbers in this interval, this would form an arithmetic progression with the first number a = 100 and the common difference d = 2.

Step 2:

The last number l  in this series is 998 .

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The nth term in the arithmetic progression is given by a + (n-1) d

so substituting the above values we get

100 + (n-1) 2 = 998

2n = 900  => n = 450

Step 3 :

Answer :

The total number of 3 digit even numbers is 450

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