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choli [55]
4 years ago
15

Which is bigger 7.79 or .99

Mathematics
2 answers:
lord [1]4 years ago
6 0
7.79 is larger than .99
Yakvenalex [24]4 years ago
4 0
7.89 is bigger than 99
You might be interested in
Let U={b, c, d, e, f, g, h} and A={b, f, g, h}. Use the roster method to write the set A'
podryga [215]

The roster method to write the set A' will be {c, d, e}.

<h3>What are Sets?</h3>

Sets are groups of clearly specified components. The number of items in a finite set is denoted by a curly bracket.

Let U = {b, c, d, e, f, g, h} and A = {b, f, g, h}.

The roster method to write the set A' will be given as,

A' = U - A

A' = {b, c, d, e, f, g, h} - {b, f, g, h}

A' = {c, d, e}

The roster method to write the set A' will be {c, d, e}.

More about the sets link is given below.

brainly.com/question/8053622

#SPJ1

4 0
1 year ago
Last year, 320 students were members of Pine Hill Middle School clubs. This year, there was a 20% increase in memberships. How m
arlik [135]

Answer:

384

Step-by-step explanation:

No. of students in the club last year = 320

No. of students in the club this year increased by 20%

To find the actual increase, 20% is multiplied by the number of students in the club last year which is 320 and to find the number of students in the club this year add the answer to 320 (the number of students in the club last year)

That is,

= 20% * 320

= 20/100 * 320

= 64

Finding the number of students in the club this year

320 + 64 = 384 students

<u>NOTE</u> : Increase means addition that is why the number of students in the club last year is added to the actual increase

3 0
3 years ago
I will give brainlest please help
Zanzabum
<h3>Answer:</h3>

The center of the circle would be (5,-8)

This is because you inverse the sign within the equation for the x/y coordinate part of it. Therefore, for this question:

(x-5)^2+(y+8)^2 = 121

The center would be (5,-8), since there is (x-5) and (y+8).

The radius of the circle would be 11

This is because within the equation for the circle, the finishing number is the radius squared. This means that if you square root this finishing number, you would get the radius. So with this question:

(x-5)^2+(y+8)^2 = 121

By doing √121, you would get 11 as the radius.

6 0
3 years ago
A case in riverhead, new york, nine different crime victims listened to voice recordings of five different men. all nine victims
Alexus [3.1K]

the complete question in the attached figure

1) Find the probability that all nine victims would select the same person. You should enter your answer as a decimal, not as a percent. Do not round, as your answer should be a terminating decimal.

P=(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)=0.000000512

2) what is the probability that the first victim picks SOMEONE? ANYONE? 

P=(1/5)=0.20  ---------------- > 20%

3) Now let’s look at victim #2. What is the probability that they pick the same person as victim #1?

P=(1/5)*(1/5)=0.04 --------------> 4%

4) Now let’s look at victim #3. What is the probability that they pick the same person as victim #1?

P=(1/5)*(1/5)*(1/5)=0.008 --------------> 0.8%

5) Now let's look at victim #9. What is the probability that they pick the same person as victim #1? 

P=(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)=0.000000512

6) Once you find all those probabilities, what rule would apply?

the probability is given by (1/5)^n

n=number of victims that pick the same person---------> in this problem = 9

P=(1/5)^9= 0.000000512

5 0
4 years ago
X + y = -4<br>y = -x + 5​
lakkis [162]

Answer:

(x,y)=(\frac{25}{9},-\frac{5}{9} )

Step-by-step explanation:

\left \{ {{x+y=-x+5} \atop {-4y=-x+5}} \right.

Simplify the expressions

\left \{ {{2x+y=5} \atop {x-4y=5}} \right.

Multiply both sides by -2

\left \{ {{2x+y=5} \atop {-2x+8y=-10}} \right.

Eliminate one variable by adding the equations

9y=-5

Divided both sides by 9

y=-\frac{5}{9}

Substitute the value of y into the equation

2x-\frac{5}{9} =5

Solve the equation

x=\frac{25}{9}

A possible solution is

(x,y)=(\frac{25}{9} ,-\frac{5}{9} )

If you need help with anything else just message me.

5 0
3 years ago
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