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Andrews [41]
3 years ago
10

Answer all the questions

Mathematics
1 answer:
just olya [345]3 years ago
7 0
You have to show us the graph or chart before we can answer your questions
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0.618 divided by 1.03
Luda [366]

0.618 divided by 1.03 will equal to 0.6

8 0
3 years ago
Read 2 more answers
Which of the<br> following is not a<br> function?<br> PLEASE HELP<br> 15 POINTS OR BRAINLIST
stira [4]

Answer:

Answer Choice D

Step-by-step explanation:

Does not pass the vertical line test but the rest of the answer choices do which makes D not a function and your solution.

Can you please make my answer the brainliest I would very much appreciate it. Thanks!

3 0
2 years ago
Lily has a bag of 30 marbles. 40% are red, 30% are green, and 30% are blue. How many marbles are green and red combined?​
RoseWind [281]
30% of the 30 marbles is nine and 9-30 = 21 so your answer is 21
3 0
3 years ago
A particle moves on the hyperbola xy=18 for time t≥0 seconds. At a certain instant, y=6 and dydt=8. What is x that this instant?
professor190 [17]

Answer:

The value of x at this instant is 3.

Step-by-step explanation:

Let x\cdot y = 18, we get an additional equation by implicit differentiation:

x\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0 (1)

From the first equation we find that:

x = \frac{18}{y} (2)

By applying (2) in (1), we get the resulting expression:

\frac{18}{y}\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0 (3)

y\cdot \frac{dx}{dt}=-\frac{18}{y}\cdot \frac{dy}{dt}

\frac{dx}{dt} = -\frac{18}{y^{2}} \cdot \frac{dy}{dt}

If we know that y = 6 and \frac{dy}{dt} = 8, then the first derivative of x in time is:

\frac{dx}{dt} = -\frac{18}{6^{2}} \cdot (8)

\frac{dx}{dt} = -4

From (1) we determine the value of x at this instant:

x\cdot \frac{dy}{dt} = -y\cdot \frac{dx}{dt}

x = -y\cdot \left(\frac{\frac{dx}{dt} }{\frac{dy}{dt} } \right)

x = -6\cdot \left(\frac{-4}{8} \right)

x = 3

The value of x at this instant is 3.

4 0
3 years ago
Show that |3+10|=|3|+ |10|?
Viefleur [7K]
|3+10|=|3|+|10|
|13|=|13|
13=13
8 0
3 years ago
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