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Veseljchak [2.6K]
3 years ago
13

Which of the following relations is NOT a function?

Mathematics
1 answer:
Rama09 [41]3 years ago
7 0

Answer:

B

Step-by-step explanation:

Hello There!

In order for a relation to be a function none of the x values can repeat

In graph b literally all of the x values are the same therefore relation b is not a function

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What is the answer for this problem 6x+3=5x
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Okay so the first thing you need to do is move the all the variables to one side of the equal sign

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Jared measured a house and its lot and made a scale drawing. The scale of the drawing was 5 millimeters : 3 meters. The actual l
alukav5142 [94]

Answer:

115mm

Step-by-step explanation:

5/x = 3/69

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4 0
3 years ago
A certain shampoo is available in two sizes. A 13.5 ounces bottle cost $2.98. A 29.2 ounce bottle cost $6.12. Find the Unit pric
Sladkaya [172]

Answer:

9.2 ounce bottle cost $6.12 is better buy with unit price of $0.22

Step-by-step explanation:

Unit price of any product is given by

unit price = weight of product/ price of product

Given sizes

A

13.5 ounces bottle cost $2.98

cost of 1 ounce of shampoo for this size = cost price/weight of shampoo

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Unit price for this size is $.022

B

9.2 ounce bottle cost $6.12

cost of 1 ounce of shampoo for this size = cost price/weight of shampoo

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Unit price for this size is $0.66

As $0.22 is less than $0.66 thus,

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6 0
3 years ago
Lim x-1 x2 - 1/ sin(x-2)
balu736 [363]

Answer:

           \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=0

Explanation:

Assuming the correct expression is to find the following limit:

         \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}

Use the property the limit of the quotient is the quotient of the limits:

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Evaluate the numerator:

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Evaluate the denominator:

  • Since         \lim_{x \to1}sin(x-2)\neq 0

                  \frac{0}{\lim_{x \to1}sin(x-2)}=0

4 0
3 years ago
Cory makes a map of his favorite park, using a coordinate system with units of yards. The old oak tree is at position (3, 7) and
Zinaida [17]

Step-by-step explanation:

.....................

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