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bixtya [17]
3 years ago
12

What is |2x-3| less than or equal to 7??

Mathematics
2 answers:
Trava [24]3 years ago
8 0
|2x-3|=2x-3 ;x≥ 3/2
|2x-3|=-2x+3;x≤3/2
zalisa [80]3 years ago
7 0
|2x-3| </= 7. This needs to be split into 2 separate inequalities, due to the | | absolute value phrase.
1) 2x-3 </= 7 --> 2x-3 +3 </= 7 +3
2x </= 10 --> x </= 5
2) 2x-3 >/= -7 --> 2x-3 +3 >/= -7 +3
2x >/= -4 --> x >/= -2
These two inequalities can be placed together as: -2 </= x </= 5
So the numbers that are correct for the original inequality are: -2, -1, 0, 1, 2, 3, 4, 5
Hope that helps!
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Need HELP PLS PIC ATTACHED
Vera_Pavlovna [14]

Answer:

4x^{2}-13x+10

Step-by-step explanation:

(4x+5)(x-2)

Multiply each term in the first parenthesis by each term in the second (foil)

Step 1: Expand it by writing out each multiplication. I added a picture showing which order to do it. (go in order of green, red, blue, yellow.) (you can remember this as first, outside, inside, last.)

When you expand it'll look like: 4x⋅x+4x⋅-2-5x-5⋅-2

Step 2: Calculate product

4x⋅x+4x⋅-2-5x-5⋅-2 (for the 4x⋅x it would be written like 4x^{2})

   4x^{2}+4x⋅-2-5x-5⋅-2

4x^{2}+4x⋅-2-5x-5⋅-2 (4x⋅-2 becomes -8x) (multiply 4x times -2)

4x^{2}-8x-5x-5⋅-2

4x^{2}-8x-5x-5⋅-2 (-5⋅-2 becomes +10) (multiply -5 times -2)

4x^{2}-8x-5x+10

Step 3: collect like terms

4x^{2}-8x-5x+10 (-8x-5x becomes -13x) (-8x times -5x)

4x^{2}-13x+10 is the most simplified so it should be your final answer

4 0
11 months ago
What can you say about the graph of the function below? check ALL that apply.
erastova [34]
I think that C and D are the correct answers
4 0
3 years ago
Find the inverse of f (x) = x + 2 + 9
Brut [27]

Answer:

y = x - 11

Step-by-step explanation:

First, turn the f(x) into a y:

y = x + 2 + 9

Now, switch the x and y.

x = y + 2 + 9

Add like terms.

2  + 9 = 11

x = y + 11

Now, solve for y. Subtract 11 on both sides.

y = x - 11

5 0
3 years ago
Does a set of rational numbers include the set of integers
NeX [460]
Yes, a set of rational numbers include the set of integers
3 0
3 years ago
If the diagonals of a parallelogram are equal, then show that it is a rectangle.
Harlamova29_29 [7]

Answer:

Given: In parallelogram ABCD, AC=BD

To prove : Parallelogram ABCD  is rectangle.

Proof : in △ACB and △BDA

AC=BD  ∣ Given

AB=BA ∣ Common

BC=AD ∣ Opposite sides of the parallelogram ABCD

△ACB ≅△BDA∣SSS Rule

∴∠ABC=∠BAD...(1) CPCT

Again AD ∥ ∣ Opposite sides of parallelogram ABCD

AD ∥BC and the traversal AB intersects them.

∴∠BAD+∠ABC=180∘ ...(2) _ Sum of consecutive interior angles on the same side of the transversal is 

180∘

From (1) and (2) ,

∠BAD=∠ABC=90∘

∴∠A=90∘ and ∠C=90∘

Parallelogram ABCD is a rectangle.

4 0
2 years ago
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