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LuckyWell [14K]
3 years ago
15

The grades on a math midterm at Springer are roughly symmetric with \mu = 78μ=78mu, equals, 78 and \sigma = 5.0σ=5.0sigma, equal

s, 5, point, 0. Omar scored 646464 on the exam. Find the z-score for Omar's exam grade. Round to two decimal places.
Mathematics
1 answer:
mr Goodwill [35]3 years ago
8 0

Answer:

-2.8

Step-by-step explanation:

Given that:

Mean, μ = 78

Standard deviation, σ = 5

Omar's score, x = 64

The Zscore of Omar's score :

Zscore = (x - μ) ÷ σ

Zscore = (64 - 78) / 5

Zscore = - 14 / 5

Zscore = - 2.8

Hence, Omar's exam score is - 2.8

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A=(-2,-7) B=(-6,4) C=(-2,7) D=(2,4) What is the perimeter?
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\displaystyle\bf\\AB=\sqrt{\Big(-6-(-2)\Big)^2+\Big(4-(-7)\Big)^2}\\\\AB=\sqrt{\Big(-6+2\Big)^2+\Big(4+7\Big)^2}\\\\AB=\sqrt{\Big(-4\Big)^2+\Big(11\Big)^2}\\\\AB=\sqrt{16+121}\\\\\boxed{\bf AB=\sqrt{137}}

.

\displaystyle\bf\\BC=\sqrt{\Big(-2-(-6)\Big)^2+\Big(7-4\Big)^2}\\\\BC=\sqrt{\Big(-2+6\Big)^2+\Big(7-4\Big)^2}\\\\BC=\sqrt{\Big(4\Big)^2+\Big(3\Big)^2}\\\\BC=\sqrt{16+9}\\\\BC=\sqrt{25}\\\\\boxed{\bf BC=5}

.

\displaystyle\bf\\CD=\sqrt{\Big(2-(-2)\Big)^2+\Big(4-7\Big)^2}\\\\CD=\sqrt{\Big(2+2\Big)^2+\Big(4-7\Big)^2}\\\\CD=\sqrt{\Big(4\Big)^2+\Big(-3\Big)^2}\\\\CD=\sqrt{16+9}\\\\CD=\sqrt{25}\\\\\boxed{\bf CD=5}

.

\displaystyle\bf\\AD=\sqrt{\Big(2-(-2)\Big)^2+\Big(4-(-7)\Big)^2}\\\\AD=\sqrt{\Big(2+2\Big)^2+\Big(4+7\Big)^2}\\\\AD=\sqrt{\Big(4\Big)^2+\Big(11\Big)^2}\\\\AD=\sqrt{16+121}\\\\\boxed{\bf AD=\sqrt{137}}

.

\displaystyle\bf\\P=AB+BC+CD+AD=\sqrt{137}+5+5+\sqrt{137}\\\\\boxed{\bf P=10+2\sqrt{137}}

 

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