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inessss [21]
3 years ago
14

Simplify 7 log3 k + 6 log3 m − 9 log3 n

Mathematics
1 answer:
kaheart [24]3 years ago
5 0
 The answer is log3 k to the seventh power m to the sixth power over n to the ninth power

a * logₓ(y) = logₓ(yᵃ)
7 log₃ (k) = log₃ (k⁷)
6 log₃ (m) = log₃ (m⁶)
9 log₃ (n) = log₃ (n⁹)

7 log₃ (k) + 6 log₃ (m) - 9 log₃ (n) = log₃ (k⁷) + log₃ (m⁶) - log₃ (n⁹)

logₓ(y) + logₓ(z) = logₓ(y * z)
log₃ (k⁷) + log₃ (m⁶) - log₃ (n⁹) = log₃ (k⁷ * m⁶) - log₃ (n⁹)

logₓ(y) - logₓ(z) = logₓ(y / z)
log₃ (k⁷ * m⁶) - log₃ (n⁹) =  log₃ (k⁷ * m⁶ / n⁹)


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Answer:

  -5, multiplicity 3; +9, multiplicity 2; -1

Step-by-step explanation:

The roots of f(x) are those values of x that make the factors be zero. For a factor of x-a, the root is x=a, because a-a=0. If the factor appears n times, then the root has multiplicity n.

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Answer:

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Step-by-step explanation:

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In the first instance, x increases by 10 from -6 and +4.  Simultaneously, y decreases by 13 from 6 to -7.

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Answer:

C. -25

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x 1 2 3 4 5

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