Simplify 7 log3 k + 6 log3 m − 9 log3 n
1 answer:
The answer is log3 k to the seventh power m to the sixth power over n to the ninth power
a * logₓ(y) = logₓ(yᵃ)
7 log₃ (k) = log₃ (k⁷)
6 log₃ (m) = log₃ (m⁶)
9 log₃ (n) = log₃ (n⁹)
7 log₃ (k) + 6 log₃ (m) - 9 log₃ (n) = log₃ (k⁷) + log₃ (m⁶) - log₃ (n⁹)
logₓ(y) + logₓ(z) = logₓ(y * z)
log₃ (k⁷) + log₃ (m⁶) - log₃ (n⁹) = log₃ (k⁷ * m⁶) - log₃ (n⁹)
logₓ(y) - logₓ(z) = logₓ(y / z)
log₃ (k⁷ * m⁶) - log₃ (n⁹) = log₃ (k⁷ * m⁶ / n⁹)
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15 - 2(- 13s + 3) = 9s - 9 + 16s
15 + 26s - 6 = 25s - 9
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26s - 25s = -9 - 9
s = - 18
You were close in the picture. 6.9
And because I prefer to be accurate, ten decimal places would be <span>6.8556546004</span>
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That will be the points corresponding to cos 60 in 3rd quadrant
which is (-1,-2)
All of the numbers are even so 2
Answer: 2
