Answer:
p = -2 ±sqrt( 5)
Step-by-step explanation:
p^2 + 4p = 1
Take the coefficient of p
4
Divide by 2
4/2 =2
Square it
2^2 = 4
Add it to each side
p^2 + 4p+4 = 1+4
(p+2) ^2 = 5
Take the square root of each side
sqrt((p+2) ^2) =±sqrt( 5)
p+2 = ±sqrt( 5)
Subtract 2 from each side
p+2-2 = -2 ±sqrt( 5)
p = -2 ±sqrt( 5)
Answer:
47
Step-by-step explanation:
180 - 133 = 47
Simple. Multiple
Monday: 6x9.75
Tuesday &Wednesday: 5x9.75
Thursday & Friday: 7x9.75
This is a problem pertaining projectile motion wherein the parameter we're finding is the angle of inclination denoted as theta. The formula to be used is the range:
Range = v^2*sin(2*theta)*(1/g)
100 = (60^2) * sin(2*theta) * (1/32.2)
theta=31.7°
I hope I was able to help you. Have a good day!
Answer:
2.02 m
or 2 m 2 cm
Step-by-step explanation:
Imagine a triangle containing the 40° angle and that this angle is at the left. Then the height of the truck bed is 1.3 m and the "shortest possible length of the ramp" is the hypotenuse of this triangle. We need to find the length of this ramp, that is, the length of the hypotenuse.
The sine function relates this 40° angle and the 1.3 m height of the truck bed:
sin 40° = opp / hyp = 1.3 m / hyp
which can be solved for 'hyp' as follows:
1.3 m
hyp = ----------------- = (1.3 m) / 0.6428)
sin 40°
1.3 m
Thus, the length of the ramp must be less than -------------- or 2.02 m
0.6428
where this last result is to the nearest cm.
If the ramp is shorter the angle of the ramp will be smaller and the ramp angle considered safer.
