Answer:
15
Step-by-step explanation:
use pathagorean theorem
♥ Answer: x=-6.9
Solve:
You need to <span>Simplify both sides of the equation.
</span>

Now: <span>Flip the equation.
</span>

<span>
</span>Lastly <span>Divide both sides by -116.85.
</span>
Final answer: x=-6.9
The complete question is
Which statement is true about the factorization of 30x² + 40xy + 51y²<span>?
A. The factorization of the polynomial is 10(3x2 + 4xy + 5y2).
B. The polynomial can be rewritten as the product of a trinomial and xy.
C. The greatest common factor of the polynomial is 51x2y2.
D. The polynomial is prime, and the greatest common factor of the terms is 1.
we know that
case A) </span>is not right because 10 is not a common factor of the three terms.
case B) is not right because the original polynomial is already a trinomial
case C) is not right because the terms do not contain 51x^2y^2
<span>case D) is right
because
</span><span>Factors of 30 are-----> 1,2,3,5,6,10,15,30
</span>Factors of 40 are-----> 1,2,4,5,8,10,20,40
Factors of 51 are-----> 1,51
<span>so
</span><span>The "Greatest Common Factor" is the largest of the common factors
</span><span>the GFC is 1
therefore
the answer is the option
</span>D. The polynomial is prime, and the greatest common factor of the terms is 1<span>
</span>
The Area of the platform is 33m²
Step-by-step explanation:
As the question says, the height of vertex from the base (D from AB) is 7m whereas the height of left vertex from the base (E from AB) is 4m
Thus it means the height of the Δ DCE (DX)= 7-4 ⇒3m
Since the platform is five-sided, the figure can be broken down into constituting parts
- Parallelogram ║ABCE
- Δ DCE
Are of the figure= Area of ║ABCE+ area Δ DCE
Area of ║ABCE= breadth * height
= 6*4 ⇒24m
²
Area Δ DCE= ½*(base)(height)
Putting the value of base is 6m and height as 3m
Area Δ DCE= ½*6*3
=9m
²
Total area= 24+9= 33m
²
Answer:
Theorem: The diagonals of a parallelogram bisect each other. Proof: Given ABCD, let the diagonals AC and BD intersect at E, we must prove that AE ∼ = CE and BE ∼ = DE. The converse is also true: If the diagonals of a quadrilateral bisect each other, then the quadrilateral is a parallelogram.
Step-by-step explanation: