<span>let:
m1 = 2xy a
m2 = 2xy b
m3 = 2x2y c
since 2 and 3 have a common factor let b=2n
m1 = 2xy a
m2 = 2xy 2 n
m3 = 2x2y c
or simply
m1 = 2xy a
m2 = 2xy 2n
m3 = 2xy 2c
given that anc have no common factors</span>
<h3>
Answer: Negative</h3>
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Explanation:
3/7 = 0.42857 approximately
Pick a number between that value and 5, not including either endpoint. Let's say we pick x = 2
Plug x = 2 into the f(x) function
f(x) = (x - 5)(2x + 7)(7x-3)
f(2) = (2 - 5)(2*2 + 7)(7*2-3)
f(2) = (2 - 5)(4 + 7)(14-3)
f(2) = (-3)(11)(11)
f(2) = -363
The actual result doesn't matter. All we're after is whether the result is positive or negative. We see the result is negative. This means f(x) is negative when 3/7 < x < 5. The f(x) curve is below the x axis on this interval.
Answer:
<em>t = 1.51</em>
Step-by-step explanation:
<u>Exponential Model</u>
The exponential model is often used to simulate the behavior of a magnitude that either grow or decay in proportion to the existing amount of that magnitude.
The model can be expressed as

In this case, Mo is the initial mass of the radioactive substance and k is a constant which value is positive if the mass is growing or negative if the mass is decaying.
The value of k is not precisely given in the question, we are assuming 
The model is now

We are required to compute the time it takes the mass to reach one-half of its initial value:

Simplifying

Taking logarithms

Solving for t

Answer: Infinite solutions.
Step-by-step explanation:

Plug the value of y into the second equation.

Add 12 on both sides.

Add 4x on both sides.

