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11111nata11111 [884]
3 years ago
9

What does it mean that stocks and bonds are relatively liquid?

Mathematics
2 answers:
solong [7]3 years ago
8 0
A) they are easier to buy and sell
yanalaym [24]3 years ago
7 0

Answer:  A. They are easier to buy and sell than other forms of investments.


Step-by-step explanation: We are all familiar with stocks and bonds. They are similar, yet different to some extent. They are two different ways to raise money. In simple language, we can say that stocks are shares of Individual companies whereas bonds are debts. Also, we can easily liquify  both of them, i.e., we can easily transform them into cash within a very short span of time, and hence, it is really easily to buy and sell them compared to other modes of investments.

Thus, the correct option is A.


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If you were to solve the following system by substitution, what would be the best variable to solve for and from what equation?2
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The second equation because they all have a common factor of 3. You can get x by itself. However, with the first one, you'll end up with fractions instead.

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Mrs. Barnes washed 2 7 of her laundry. Her son washed 1 4 of it. Who washed most of the laundry? How much of the laundry still n
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Step-by-step explanation:

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Y=1/3x while m=0................

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2 years ago
Average precipitation for the first 7 months of the year, the average precipitation in toledo, ohio, is 19.32 inches. if the ave
Colt1911 [192]
Part A:

The probability that a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \  \frac{a-\mu}{\sigma}\right)

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>a randomly selected year will have precipitation greater than 18 inches for the first 7 months is given by:

P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\  \\ =1-P\left(z\ \textless \ \frac{18-19.32}{2.44}\right) \\  \\ =1-P(z\ \textless \ -0.5410) \\  \\ =1-0.29426=\bold{0.7057}



Part B:

</span>The probability that an n randomly selected samples of a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \ \frac{a-\mu}{\frac{\sigma}{\sqrt{n}}}\right)

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>5 randomly selected years will have precipitation greater than 18 inches for the first 7 months is given by:

</span>P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\ \\ =1-P\left(z\ \textless \ \frac{18-19.32}{\frac{2.44}{\sqrt{5}}}\right) \\ \\ =1-P(z\ \textless \ -1.210) \\ \\ =1-0.1132=\bold{0.8868}
7 0
3 years ago
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