Answer:
A = 6x² + 97x + 391
Step-by-step explanation:
Given that,
The length of the shop, l = (3x+23)
The width of the shop, b = (2x+17)
The expression for the area of the shop is given by :
A = lb
Put all the values,
A = (3x+23) × (2x+17)
= 6x² +51x+46x +391
= 6x² + 97x + 391
Hence, the expression for the area of the shop is equal to 6x² + 97x + 391.
12h + 30w.....where h = hrs worked and w = wagons sold
so if an employee works 6 hrs and sells 3 wagons....then h = 6 and w = 3
12h + 30w
12(6) + 30(3) =
72 + 90 = $ 162 <==
Answer: 3630
Step-by-step explanation:
Given that:
Volume of container = 98,000 cubic volume
Volume of cabinet = 27 cubic volume
The number of cabinets which the container will. Hold equals:
Volume of container / volume of cabinet
= 98000 cubic volume / 27 cubic volume
= 3629.6296
The container will hold approximately 3630 27 cubic volume of cabinet.
Answer:
48
Step-by-step explanation:
You are solving for the mean of the data set. To do so, add all the numbers together, and <em>divide by the amount of numbers in the set</em>.
Note that there are 4 numbers given to you: 38, 40 , 53, 61.
First, add the 4 numbers together:
38 + 40 + 53 + 61 = 192
Next, divide 4 from the total gotten:
192/4 = 48
48 is the mean of the data set.
~
Answer:
The probability that at least 1 car arrives during the call is 0.9306
Step-by-step explanation:
Cars arriving according to Poisson process - 80 Cars per hour
If the attendant makes a 2 minute phone call, then effective λ = 80/60 * 2 = 2.66666667 = 2.67 X ≅ Poisson (λ = 2.67)
Now, we find the probability: P(X≥1)
P(X≥1) = 1 - p(x < 1)
P(X≥1) = 1 - p(x=0)
P(X≥1) = 1 - [ (e^-λ) * λ^0] / 0!
P(X≥1) = 1 - e^-2.67
P(X≥1) = 1 - 0.06945
P(X≥1) = 0.93055
P(X≥1) = 0.9306
Thus, the probability that at least 1 car arrives during the call is 0.9306.
