Can square root of 27 be simplified

Mathematics

2 answers:

Studentka2010 [4]3 years ago

8 0

Yes, square root of 27 can be simplified

$\sqrt{27}= \sqrt{9*3}=3 \sqrt{3}$

irga5000 [103]3 years ago

5 0

The roots up to 27 are 1 4 9 16 and 25. 9 is a factor of 27 so the answer is yes.
To take 9 out, write the root on the left side (3) and write what is left on the right (3 since 9 times 3 is 27) The answer to root 27 simplified is 3 root 3

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Write down in terms of n, an expression for the nth term of the following sequences: 1,8,15,22,29

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Step-by-step explanation:

t1 = 1 = 7*1 - 6

t2 = 8 = 7* 2 - 6

t3 = 15 = 7 * 3 - 6

t4 = 22 = 7 *4 - 6

t5 = 29 = 7 * 5 - 6

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6 0

3 years ago

Read 2 more answers

How to solve this question

VMariaS [17]

The variance method is as follows.

-Sum the squares of the values in data set, and then divide by the number of values in data set
- From that, subtract the square of the mean (add all values and divide by number of values in the data set)

Our variance is

 $\displaystyle\sigma^2 = \frac{2^2 + 5^2 + m^2}{3} - \left(\frac{2 + 5 + m}{3}\right)^2$

Since variance has to be 14, we set $\sigma^2 = 14$ and solve for m

$14= \frac{4 + 25 + m^2}{3} - \left(\frac{7 + m}{3}\right)^2\ \Rightarrow \\ \\
14 = \frac{29}{3} + \frac{1}{3}m^2 - \frac{1}{9}(7+m)^2 \\ \\
14 = \frac{29}{3}+ \frac{1}{3}m^2 - \frac{1}{9}(49 + 14m + m^2) \\ \\
14 = \frac{29}{3}+ \frac{1}{3}m^2 - \frac{49}{9}- \frac{14}{9}m- \frac{1}{9}m^2 \\ \\
0 = \frac{-88}{9} -\frac{14}{9}m + \frac{2}{9}m^2
$

quadratic formula

$m = \displaystyle\frac{-b \pm \sqrt{b^2 -4ac}}{2a} \\
m = \frac{-(-\frac{14}{9}) \pm \sqrt{\left(-\frac{14}{9}\right)^2 - 4(2/9)(-88/9)} }{2(2/9)} \\
m = \frac{\frac{14}{9} \pm \sqrt{ \frac{196}{81} + \frac{704}{81} } }{\frac{4}{9} } \\
m = \frac{\frac{14}{9} \pm \sqrt{ \frac{900}{81} } }{\frac{4}{9} } \\
m = \frac{\frac{14}{9} \pm \sqrt{ \frac{100}{9} } }{\frac{4}{9} } \\
m = \frac{\frac{14}{9} \pm \frac{10}{3} }{\frac{4}{9} } \\
m = 11, -4$

-4 doesnt' work as it is not a positive integer

m = 11

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