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inna [77]
3 years ago
5

Can square root of 27 be simplified

Mathematics
2 answers:
Studentka2010 [4]3 years ago
8 0
<span>Yes, square root of 27 can be simplified
</span>
\sqrt{27}= \sqrt{9*3}=3 \sqrt{3}


irga5000 [103]3 years ago
5 0
The roots up to 27 are 1 4 9 16 and 25. 9 is a factor of 27 so the answer is yes.
To take 9 out, write the root on the left side (3) and write what is left on the right (3 since 9 times 3 is 27) The answer to root 27 simplified is 3 root 3
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Answer:

<h2>(g \: \circ \: f)(0) = 17</h2>

Step-by-step explanation:

f(x) = 2x + 4

g(x) = 4x² + 1

In order to find (g ∘ f)(0) we must first find

(g ° f )(x)

To find (g ° f )(x) substitute f(x) into g(x) that's for every x in g(x) replace it with f(x)

That's

<h3>(g \: \circ \: f)(x) = 4( ({2x + 4})^{2} ) + 1 \\  = 4(4 {x}^{2}  + 16x + 16) + 1 \\  =  {16x}^{2}  + 64x + 16 + 1</h3>

We have

<h3>(g \: \circ \: f)(x) =  {16x}^{2}  + 64x + 17 \\</h3>

Now to find (g ∘ f)(0) substitute the value of x that's 0 into (g ∘ f)(0)

We have

<h3>(g \: \circ \: f)(0) = 16( {0})^{2}  + 64(0) + 17 \\</h3>

We have the final answer as

<h3>(g \: \circ \: f)(0) = 17</h3>

Hope this helps you

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