I’m pretty sure it’s y=.5 and x=-2 so just put that into slop intercept form
Answer: 4(3+1)/4c-q^1/2d i think tht is how you do it...
Step-by-step explanation:
apply the distribuitive property to create an equivalent expression
4
(
3
+
1
)
4
c
−
q
1
2
d
Write the problem as a mathematical expression.
apply the distribuitive property to create an equivalent expression
4
(
3
+
1
)
4
c
−
q
1
2
d
Simplify.
4
(
3
+
1
)
4
c
−
q
2
d
Add
3
and
1
.
4
⋅
4
4
c
−
q
2
d
Simplify the denominator.
Tap for more steps...
4
⋅
4
8
c
d
−
q
2
d
Multiply
4
by
4
.
16
8
c
d
−
q
2
d
Multiply the numerator by the reciprocal of the denominator.
16
2
d
8
c
d
−
q
Multiply
16
2
d
8
c
d
−
q
.
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32
d
8
c
d
−
q
Answer:
12
Step-by-step explanation:
Alright so we are asked to find the intersection of y=(x-8)^2 and y=36.
So plug second equation into first giving: 36=(x-8)^2.
36=(x-8)^2
Take square root of both sides:

Add 8 on both sides:

x=8+6=14 or x=8-6=2
So we have the two intersections (14,36) and (2,36).
We are asked to compute this length.
The distance formula is:




.
I could have just found the distance from 14 and 2 because the y-coordinates were the same. Oh well. 14-2=12.
Answer:
It is unclear what exaclty the kind of answer is you are looking for.
Step-by-step explanation:
adding- 11
subtracting- 1 or -1
multiplying- 30
dividing- 1.2 or 0.8333333
Answer:
d
Step-by-step explanation:
the Selling price of the first pipe = $1.20
Profit = 20%
Let’s try to find the cost price of the first pipe
CP = Selling price - Profit
CP = 1.20 - 20% of CP
CP = 1.20 - 0.20CP
CP + 0.20CP = 1.20
1.20CP = 1.20
CP = 1.201.20
CP = $ 1
the Selling price of the Second pipe = $1.20
Loss = 20%
Let’s try to find the cost price of the second pipe
CP = Selling price + Loss
CP = 1.20 + 20% of CP
CP = 1.20 + 0.20CP
CP - 0.20CP = 1.20
0.80CP = 1.20
CP = 1.200.80
CP = $1.50
Therefore, total cost price of the two pipes = $1.00 + $1.50 = $2.50
And total selling price of the two pipes = $1.20 + $1.20 = $2.40
Loss = $2.50 – $2.40 = $0.10
Therefore, Mr. Jones lost 10 cents.