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3 years ago

IM GOING TO FLORIDA TOMORROW FOR A WEEK!!! (just thought i would let everybody know Lol

Mathematics

2 answers:

netineya [11]3 years ago

7 0

The answer is 16
Explanation for the questions
8\2(2+2)

8\2(4)

4(4)

16

Hope u have fun in Florida

bearhunter [10]3 years ago

5 0

Answer:16

Step-by-step explanation:

8÷2(2+2)

8÷2(4)

4(4)

Have fun in Florida!

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Tax" is an added amount when finding the grand total of a bill. True or false

galben [10]

Answer:

Step-by-step explanation:

True

5 0

3 years ago

Read 2 more answers

there are 36 capenters in a crew. Ona certain day,29 were present .What percent showed up for work?[round to the nearest tenth

aliina [53]

Answer:

Step-by-step explanation:

We assume, that the number 36 is 100% - because it's the output value of the task.

2. We assume, that x is the value we are looking for.

3. If 100% equals 36, so we can write it down as 100%=36.

4. We know, that x% equals 29 of the output value, so we can write it down as x%=29.

5. Now we have two simple equations:

1) 100%=36

2) x%=29

where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:

100%/x%=36/29

6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for 29 is what percent of 36

100%/x%=36/29

(100/x)*x=(36/29)*x - we multiply both sides of the equation by x

100=1.24137931034*x - we divide both sides of the equation by (1.24137931034) to get x

100/1.24137931034=x

80.5555555556=x

x=80.5555555556

now we have:

29 is 80.5555555556% of 36 to the nearest tenth is 81%

4 0

3 years ago

A population of fish in a lake is 14000 in 2010. The population decreases 6% annually. What is the population in 2019

kodGreya [7K]

Answer:

8022.

Step-by-step explanation:

Let x be the number of years after 2010.

We have been given a population of fish in a lake is 14000 in 2010. The population decreases 6% annually.

We can see that population of fish is the lake is decreasing exponentially as it is decreasing 6% annually.

Since we know that an exponential function is in form: $y=a*b^x$ , where,

a = Initial value,

b = For decrease or decay b is in form (1-r) where r represents decay rate in decimal form.

Let us convert our given decay rate in decimal form.

$6\5=\frac{6}{100}=0.06$

Upon substituting our given values in exponential form of function we will get the population of fish in the lake after x years as:

$y=14,000*(1-0.06)^x$

$y=14,000*(0.94)^x$

Let us find x by subtracting 2010 from 2019.

$x=2019-2010=9$

Upon substituting x=9 in our function we will get,

$y=14,000*(0.94)^9$

$y=14,000*0.5729948022286167$

$y=8021.927\approx 8022$

Therefore, the population of fish in 2019 will be 8022.

6 0

3 years ago

A cement walkway of uniform width has been built around an in-ground rectangular pool. the area of the walkway is 1344 square fe

Elza [17]

Answer:

6 feet.

Step-by-step explanation:

Dimensions of the Pool =80 feet long by 20 feet wide

Area of the walkway =1344 square feet.

If the width of the walkway=w

Length of the Larger Rectangle =80+2w
Width of the Larger Rectangle =20+2w

Area of the Walkway =Area of the Larger Rectangle - Area of the Pool

$1344=(80+2w)(20+2w)-(80*20)\\1344=80*20+160w+40w+4w^2-80*20\\4w^2+200w=1344\\4w^2+200w-1344=0\\We factorize\\4(w^2+50w-336)=0\\4(w^2-6w+56w-336)=0\\w(w-6)+56(w-6)=0\\(w-6)(w+56)=0\\w-6=0$ or $ w+56=0\\w=6$ ft or $ w=-56$ \\Therefore, the width of the walkway , w=6 feet.$