Hello!

We can begin by solving for c₃ given the equations:
c₃ = 3c₂ + 2c₁ - 2
c₃ = 3(2) + 2(4) - 2
Simplify:
c₃ = 6 + 8 - 2 = 12
We can now find the subsequent terms:
c₄ = 3(12) + 2(2) - 2 = 38
c₅ = 3(38) + 2(12) - 2 = 136
Answer: (x-6)(x+1)
Step-by-step explanation:
Sum : x2 − 5 x- 6
x2 + x-=6 x − 6
factor pair: x 2 + x − 6 x − 6
x( x+ 1 ) − 6 ( x + 1 )
rewrite from: x (x + 1 ) − 6 ( x + 1 )
(x-6)(x+1)
I'm not 100 percent sure but I think is e