A linear approximation to the error in volume can be written as
... ∆V = (∂V/∂d)·∆d + (∂V/∂h)·∆h
For V=(π/4)·d²·h, this is
... ∆V = 2·(π/4)·d·h·∆d + (π/4)·d²·∆h
Using ∆d = 0.05d and ∆h = 0.05h, this becomes
... ∆V = (π/4)·d²·h·(2·0.05 + 0.05) = 0.15·V
The nominal volume is
... V = (π/4)·d²·h = (π/4)·(2.2 m)²·(6.8 m) = 25.849 m³
Then the maximum error in volume is
... 0.15V = 0.15·25.849 m³ ≈ 3.877 m³
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Essentially, the error percentage is multiplied by the exponent of the associated variable. Then these products are added to get the maximum error percentage.
1) -12
ab is a times b. We plug in the numbers (-4)*(3) which equals -12.
2) 1
We plug in -4 for a, and 3 for b into the equation.
We get 2(-4) + 3(3)
2*-4 is -8. 3*3 is 9. We add them both, and -8+9 equals 1.
3) -14
We plug in -4 for a, and 3 for b into the equation.
2(-4-3)
-4-3 is -7. -7*2 equals -14.
Where's the picture or the papper or the problem I would help but I can't see it
Answer: {-16,4,92}. 2) {-16,10 ,42}. 3) {0,10,42}. 4) {0,4,92}. 5 The function f(x) = 2x. 2 + 6x - 12 has a domain.
Step-by-step explanation:
60.44 is greater than 60.3
-you can see this when you subtract 60.3 from 60.44 this would leave a 0.11 which is a positive number.
-thus meaning 60.44 is larger/greater.
