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3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!Which expression is equal to 5/13√ ?

Mathematics

2 answers:

Anvisha [2.4K]3 years ago

7 0

$\dfrac{5}{\sqrt{13}}\cdot\dfrac{\sqrt{13}}{\sqrt{13}}=\dfrac{5\sqrt{13}}{13}$

$\text{Used:}\ \sqrt{a}\cdot\sqrt{a}=a$

Mariana [72]3 years ago

5 0

Answer:

5√13 / 13

Step-by-step explanation:

If we have the expression:

We can only change the way it is expressed by multiplying it by 1 to not change the value and we know that1 is the same as a number divided by the same number:

In this case, we are going to multiply the expression by <em>√13 / √13 which is equal to 1:</em>

<em>(5 / √13) * (√13 / √13)</em>

Solving we get:

5*√13 / 13

<em />

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The Toylot company makes an electric train with a motor that it claims will draw an average of only 0.8 ampere (A) under a norma

kotegsom [21]

Answer:

Test statistic = 3.1587

Step-by-step explanation:

We are given that the Toy-lot company makes an electric train with a motor that it claims will draw an average of only 0.8 ampere (A).

Also, a sample of eleven motors was tested, and it was found that the mean current was x = 1.20 A, with a sample standard deviation of s = 0.42 A.

So, Null Hypothesis, $H_0$ : $\mu$ = 0.8 { claim of 0.8 A is not low}

Alternate Hypothesis, $H_1$ : $\mu$ > 0.8 { claim of 0.8 A is too low}

Now, the test statistics used here will be;

T.S. = $\frac{Xbar - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, X bar = sample mean = 1.20 A

s = sample standard deviation = 0.42 A

n = sample size = 11 motors

So, Test statistics = $\frac{1.20 - 0.8}{\frac{0.42}{\sqrt{11} } }$ ~ $t_1_0$

= 3.1587

At 1% level of significance, t table gives a critical value of 2.764 at 10 degree of freedom. Since our test statistics is higher than the critical value so we have sufficient evidence to reject null hypothesis .

Therefore, we conclude that Toy-lot claim of 0.8 A is too low.

8 0

4 years ago

The standard deviation of a sample taken from population A is 17.6 for a sample of 25.

lawyer [7]

Answer:

The standard deviation of the sample mean differences is _5.23_

Step-by-step explanation:

We have a sample of a population A and a sample of a population B.

For the sample of population A, the standard deviation $\sigma_A$ is

$\sigma_A = 17.6$

The sample size $n_A$ is:

$n_A = 25$ .

For the sample of population B, the standard deviation $\sigma_B$ is

$\sigma_B = 21.2$

The sample size $n_B$ is:

$n_B = 30$ .

Then the standard deviation for the difference of means has the following form:

$\sigma=\sqrt{\frac{\sigma_A^2}{n_A}+\frac{\sigma_B^2}{n_B}}$

Finally

$\sigma=\sqrt{\frac{17.6^2}{25}+\frac{21.2^2}{30}}\\\\\sigma= 5.23$

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4 years ago

Use the distributive property to rewrite 30d+18

Vladimir [108]

Im assuming you just want to take out common multiples so,
30d+18 is also the same as 6(5d+3)

8 0

3 years ago

Two gears are connected and are rotating simultaneously. The smaller gear has a radius of 3 inches, and the larger gear has a ra

vaieri [72.5K]

Let r represent the radius of the smaller circle and R the radius of the larger
circle.

Apply ratios: the radius of the smaller circle to the radius of the larger circle.

r: R = 3 : 7.

I complete rotation = 360 degrees.

1st:

For one complete rotation of the smaller circle, the larger circle is rotated through (3/7)*(360) = 154.3 degrees

2nd:For one complete rotation of the larger circle, the larger circle is rotated through (7/3)*(360) = 840.0 degrees

This is equivalent to (840/360) = 2.3 rotations

Alternatively, use the ratios: The number of rotations = R/r = 7/3 = 2.3 rotations

Hope this helped☺☺

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3 years ago

Simplify please and show steps:<br><br> Sec (x) tan (x) csc (x) cot (x) sin (x) cos (x)

Airida [17]

Answer:

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Step-by-step explanation:

First of all transform the expression using trigonometric identities

That's

$\sec(x) = \frac{1}{ \cos(x) }$