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guapka [62]
3 years ago
15

Which expressions equal 9 when x=4 and y=1/3

Mathematics
2 answers:
Maslowich3 years ago
6 0
B.
4 \times 2 = 8
3 \times  \frac{1}{3}  = 1
8 + 1 = 9
babymother [125]3 years ago
6 0
I think there are 3 answers, B, D, and E.

For B: 2(4)+3(1/3)=8+1=9
For D: 5(4/2)-3(1/3)=5(2)-1=10-1=9
For E: 3(4)-9(1/3)=12-3=9
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What is 6/10 rounded to the nearest half
belka [17]

6/10 rounding to the nearest half would be 1, not 0.

Reason for this: Here is a number line to help you!

|----|----|

Left line = 0

Middle line = 1/2

Right line = 1

Here is another rule!

0/10, 1/10, 2/10, 3/10, 4/10 = rounded to the nearest half would be 0

5/10, 6/10, 7/10, 8/10, 9/10, 10/10 = rounded to the nearest half would be 1.

So 6/10 rounded to the nearest half is 1.

Hope this helped!

Plz mark brainliest!

5 0
3 years ago
Factor the polynomial below. 6x3y3z 12x2y2z3
laiz [17]
<span>The answer is 6x^2y^2z(xy+2z^2).</span>
8 0
3 years ago
Read 2 more answers
A publishing company claims that in fall 2019, the average price of college textbooks for a single semester is $385. Suppose you
hram777 [196]

Answer:

We accept H₀ . We don´t have enough evidence to express the publisher claim is not true

Step by Step explanation:

We must evaluate if the mean of the price of college textbooks is different from the value claimed by the publisher

n < 30 then we must use t - distrbution

degree of freedom   n  - 1     df = 22 - 1     df = 21

As the question mentions " different " that means,  a two-tail test

At 0,01 significance level     α  = 0,01       α/2  =  0,005

and t(c)  = 2,831

Test Hypothesis

Null Hypothesis                      H₀          μ  =  μ₀

Alternative hypothesis           Hₐ          μ  ≠  μ₀

To calculate t(s)

t(s)  =  (  μ  -  μ₀ ) /σ/√n

t(s)  =  (  433,50 - 385 ) / 86,92 / √22

t(s)  =  2,6171

Comparing   t(c)   and t(s)

t(s) < t(c)

Then  t(s) is in the acceptance region we accept H₀. We don´t have enough evidence to claim that mean price differs from publisher claim

6 0
3 years ago
What is 2.318 repeating as a mixed number?
ioda
The idea being, we first, move the repeating part to the left of the decimal point, by simply multiplying it by a power of 10, in this case, we need to move 318, so we need then 1000, 3 decimals, 3 zeros.

and we'll make the expression a variable, so let's do so first,

\bf \boxed{x=2.318318\overline{318}}\\\\&#10;-------------------------------\\\\&#10;\begin{array}{llll}&#10;1000\cdot x&=&2318.318\overline{318}\\&#10;&&2316+2.318318\overline{318}\\&#10;&&2316+x&#10;\end{array}\implies 1000x=2316+x&#10;\\\\\\&#10;999x=2316\implies x=\cfrac{2316}{999}\implies x=\cfrac{772}{333}\implies x=2\frac{106}{333}
4 0
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Which statement describes the system of equations?
Strike441 [17]

Answer:

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x-2y=2......(2)

(substrate 1 in 2

x=2

substitutes x in 1

2+2y=2

4y=2

y=4/2

y=2

8 0
3 years ago
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