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Trava [24]
2 years ago
13

Find an equation of the line L that passes through the point (2,-12) and satisfies the given condition.

Mathematics
1 answer:
mote1985 [20]2 years ago
7 0

Answer:

y = 1/4 x - 12.5

Step-by-step explanation:

8x + 2y = -8 (rewrite in y = mx + b form)

2y = -8x -8 (divide both sides by 2)

y = -4x -2 for first line

Perpendicular line L has "opposite/inverse" slope

y = -4x + b becomes y = 1/4 x + b

What's b (the y-intercept)?

Plug the point (2, -12) into the equation y = 1/4 x  + b to solve for b

-12 = 1/4 (2) + b

-12 = 1/2 + b (subtract 1/2 from both sides)

-12.5 =b (rewrite equation)

y = 1/4 x - 12.5

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Pls help and show workings
andreev551 [17]

Answer: x = 11

Step-by-step explanation:

same as the last question, set them as equal and solve. here's my work:

<em>5x - 1 = 4x + 10</em>

<em>5x - 1 (+ 1) = 4x + 10 (+ 1)</em>

<em>5x = 4x + 11</em>

<em>5x (- 4x) = 4x (- 4x) + 11</em>

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2 years ago
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Answer:

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The cosecant is the reciprocal of the sine.

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Read 2 more answers
What is the equation of the line perpendicular to 2x − 5y = −35 that contains the point (10, 4)?
Gnoma [55]
Perpendicular has slope that multiplies to -1 in other sloope

thsi one

2x-5y=-35
-5y=-2x-35
y=2/5x+7
slope=2/5
2/5 times -5/2=-1
y=-5/2x+b
findn b
(10,4)
(x,y)
4=-5/2(10)+b
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21=b
y=-5/2x+21
2y=-5x+42
5x+2y=42
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