Volume of a cone = <span>πr^2(h/3)
r=6
h=27
v = </span><span>π(6^2)27/3
v = </span><span>π (36)(9)
v=</span><span>π324 in. cubed
or
v=1,017.36 in. cubed </span>
Answer:
B. y = x +3
Step-by-step explanation:
The fastest way to find this answer is to substitute offered values of x and y into the given equations to see if they are true.
<h3>Substitution</h3>
Using the first line in the table, (x, y) = (2, 5), we have ...
A 5 = 2(2) . . . . false
B 5 = 2 +3 . . . . true
C 5 = 3(2) . . . . false
D 5 = 2 +1 . . . . false
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<em>Additional comment</em>
Checking answer choices against the problem statement is one of many possible strategies for answering multiple-choice questions.
Answer:
The answer to this question would be B:
Based on the question, since the weight of the weight plates are 20 lbs, this would be represented by the 20x in the function. As well, the 5 lb barbell would be represented by the 5 in the function. The range of the function is determined by the amount of weight plates are added. So if I added one weight plate the equation would equal, f(x) = 20(1) + 5 = 25. This continues on the more and more weight plates you add.
Hope this reached you well :)
Step-by-step explanation:
20 = weight of the weight plates
x = amount of weight plates.
5 = weight of the barbell
f(x) = 20(0) + 5 = 5
f(x) = 20(1) + 5 = 25
f(x) = 20(2) + 5 = 45
f(x) = 20(3) + 5 = 65
f(x) = 20(4) + 5 = 85
Answer:
6
Step-by-step explanation:
You have to find what to multiply by to get to the next term
-30 ÷ -5 = 6
- 180 ÷ -30 = 6
therfore the common ratio is 6
