All categories

3 years ago

What is five x plus negative three equals fifteen

2 answers:

7 0

You write the equation like this:
$5x + (-3) = 15$

But if you want to solve it then you do it like this:
$5x + (-3) = 15$
$5x - 3 = 15$
$5x = 18$
$x = 18/5$

Anvisha [2.4K]3 years ago

3 0

5x+(-3)=15
+ 3. +3
5x=18
/5. /5
x=18/5

x=18/5 or x=3 3/5

You might be interested in

Evaluate: (8/27)^-2/3 <br><br> add: sqroot(27) + sqroot (75)

vredina [299]

The answer to the first question
is 2 1/4.
The answer to the second question is 8 sqroot 3. Hope I was able to help

3 0

3 years ago

Find the surface area of the figure.

Mariana [72]

Answer:

174m²

Step-by-step explanation:

SA = 2(wl + hl + hw)

= 2(5m x 11m + 2m x 11m + 2m x 5m)

= 2(55m² + 22m² + 10m²)

= 2 x 87m²

=174m²//

4 0

1 year ago

(10.02)

melisa1 [442]

Answer:

$sin O=\dfrac{3\sqrt{13}}{13}\\cos O=\dfrac{2\sqrt{13}}{13}\\tan O=\dfrac{3}{2}$

Step-by-step explanation:

If the point (2,3) is on the terminal side of an angle in standard position.

Adjacent of O, x=2,

Opposite of O, y=3

Next, we determine the hypotenuse, r using Pythagoras Theorem.

$Hypotenuse =\sqrt{Opposite^2+Adjacent^2} \\r=\sqrt{3^2+2^2} \\r=\sqrt{13}$

Therefore:

$sin O=\dfrac{Opposite}{Hypotenuse} \\sin O=\dfrac{3}{\sqrt{13}} \\$Rationalizing\\sin O=\dfrac{3\sqrt{13}}{13}$

$cos O=\dfrac{Adjacent}{Hypotenuse} \\cos O=\dfrac{2}{\sqrt{13}} \\$Rationalizing\\cos O=\dfrac{2\sqrt{13}}{13}$

$Tan O=\dfrac{Opposite}{Adjacent} \\tan O=\dfrac{3}{2}$

4 0

3 years ago

2(x+2)-5=3(x+1)

Eva8 [605]

Answer:

$\huge \fbox \pink {A}\huge \fbox \green {n}\huge \fbox \blue {s}\huge \fbox \red {w}\huge \fbox \purple {e}\huge \fbox \orange {r}$

$2(x + 2) - 5 = 3(x + 1) \\ 2x + 4 - 5 = 3x + 3 \\ 2x - 1 = 3x + 3 \\ - 1 - 3 = 3x - 2x \\ - 4 = x$

5 0

3 years ago

Read 2 more answers

HELLLLLLLP MEEEEEEE!!!!

matrenka [14]

Answer:

the answer are B,=6506/82=79.3

C)7031/89=79

the answer are B and C

but maybe option C maybe also right because it is 3193/38=84

7 0

3 years ago

Read 2 more answers