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4 years ago

What is five x plus negative three equals fifteen

2 answers:

7 0

You write the equation like this:
$5x + (-3) = 15$

But if you want to solve it then you do it like this:
$5x + (-3) = 15$
$5x - 3 = 15$
$5x = 18$
$x = 18/5$

Anvisha [2.4K]4 years ago

3 0

5x+(-3)=15
+ 3. +3
5x=18
/5. /5
x=18/5

x=18/5 or x=3 3/5

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3 years ago

Read 2 more answers

A circle with center C(4, -2) passes through the point A(1, 3). Does the point B(8, -2) lie inside the circle?

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Yes, point B will lie inside the circle.

Step-by-step explanation:

Let the distance between point C and point A be the radius of our given circle.

We have been given that a circle with center C(4, -2) passes through the point A(1, 3).

Since we know that a point will lie inside circle if the distance between the point and center of circle is less than radius of circle.

Let us find distance between points C and A using distance formula.

$\text{Radius}=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

$\text{Radius}=\sqrt{(4-1)^{2}+(-2-3)^{2}}$

$\text{Radius}=\sqrt{(3)^{2}+(-5)^{2}}$

$\text{Radius}=\sqrt{9+25}$

$\text{Radius}=\sqrt{34}$

Radius of our circle is $\sqrt{34}$ . Now let us find distance between center of our circle and point B.

$\text{Distance between C and B}=\sqrt{(4-8)^{2}+(-2--2)^{2}}$

$\text{Distance between C and B}=\sqrt{(-4)^{2}+(-2+2)^{2}}$

$\text{Distance between C and B}=\sqrt{16+(0)^{2}}$

$\text{Distance between C and B}=\sqrt{16}$

$\text{Distance between C and B}=4$

We can see that distance of point B from center of our given circle is less than distance between point A and center of circle, therefore point B will lie inside the circle.

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3 years ago

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A gym charges an initial fee plus $25 per month. John paid $200 for six months. Assume the relationship is linear.

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Step-by-step explanation:

a. The rate of change is $33.33 per month

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This means that in addition to the initial fee, Josh has to pay $33.33 per month for the gym membership.

b. The initial value is $25. This is a constant value and a one time fee to open and attain a gym membership.

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