Help me help me!!!!!!!

Approximately how long is a leg of an isosceles right triangle that has a hypotenuse of length 11.31

Lapatulllka [165]

Answer:

Leg of an isosceles right triangle is 7.99 long.

Step-by-step explanation:

Given:

Length of the hypotenuse =11.31

To find:

Length of the leg of an isosceles right triangle =?

Solution:

According to Pythagorean's Theorem, we have

$a^2 +b^2 = c^2$ -----------------------------(1)

Here were are given as isosceles triangle, so the two sides will be of same length

So equation 1 can be rewritten as

$a^2 +a^2 = c^2$

$2a^2 = c^2$

Substituting the value of hypotenuse

$2a^2 = (11.31)^2$

$2a^2 = 127.91$

$a^2 = \frac{127.91}{2}$

$a^2 =63.955$

$a = \sqrt{63.955}$

a = 7.99

7 0

3 years ago

Jeremy ate 5 pieces of shrimp, Julie ate 7 pieces. What fraction of the total did Jeremy eat?

matrenka [14]

Answer:

$\frac{5}{12}$

Step-by-step explanation:

The total amount of shrimp that was eaten was 12 pieces of shrimp.

To make the fraction you will simply put the amount of shrimp Jeremy ate over the total number of shrimp eaten by the pair.

Therefore, the fraction would look like this:

$\frac{5}{12}$

The decimal form of this would be 0.4167. Which also means that Jeremy ate 41.67% of the total amount of shrimp eaten.

Hope this helps!!

4 0

2 years ago

Can someone help me with this plz?

vredina [299]

I believe it is 21 and all so if u are having trouble in mathematics a good app to have is Pappa math algebraic calculator

3 0

3 years ago

Read 2 more answers

How can I simplify this and show work?

svp [43]

$\frac{ \sqrt{3}}{ \sqrt{5} - \sqrt{6} } \\ = \frac{ \sqrt{3}( \sqrt{5} + \sqrt{6}) }{( \sqrt{5} - \sqrt{6})( \sqrt{5} + \sqrt{6})} \\ = \frac{ \sqrt{15}+3 \sqrt{2} }{5-6} \\ =- \sqrt{15}-3 \sqrt{2}$
Please vote me the Brainliest one. Thank you <3

6 0

3 years ago

Determine and describe the number and type of roots of the quadratic functions. Show any and all work necessary to determine

algol13

Answer:

See explanations below

Step-by-step explanation:

The root of a quadratic equation is determined by its discriminant

D = b²-4ac

If D > 0, the roots are real and unique

If D < 0, the roots are complex

If D= 0, the roots are real and equal

a) For the quadratic equation

y=3x^2+7x+8

Since the highest degree of the equation is 2, hence the equation will have 2 roots

From the equation, a = 3, b = 7 and c = 8

Get the discriminant

D = 7²-4(3)(8)

D = 49 - 96

D = -47

Since the discriminant value is less than 0, hence the roots are complex roots

b) For the quadratic equation

y=2x^2-7x-2

Since the highest degree of the equation is 2, hence the equation will have 2 roots

From the equation, a = 2, b = -3 and c = -2

Get the discriminant

D = (-3)²-4(2)(-2)

D = 9 + 16

D = 25

Since the discriminant value is greater than 0, hence the roots are real and unique.

c) For the quadratic equation

y=9x^2+30x+25

Since the highest degree of the equation is 2, hence the equation will have 2 roots

From the equation, a = 9, b = 30 and c = 25

Get the discriminant

D = 30²-4(9)(25)

D = 900 - 900

D = 0

Since the discriminant value is equal to 0, hence the roots are complex real and equal

7 0

3 years ago