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schepotkina [342]
3 years ago
13

Help me help me!!!!!!!

Mathematics
1 answer:
fgiga [73]3 years ago
4 0
Quadratic its quadratic

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Step-by-step explanation:

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Cloud nine is having a sale on all shirts and pants in the store.Olivia purchased 8 shirts 4 pairs of pants for $176.Raheem purc
mihalych1998 [28]

Question is Incomplete; Complete question is given below;

Cloud Nine is having a sale on all shirts and pants in the store. Olivia purchased 8 shirts and 4 pairs of pants for $176. Raheem purchased 3 shirts and 4 pairs of pants for $116. Let x represent the price of a shirt and y represent the price of a pair of pants. Write a system of equations, and use the elimination method to find a reasonable price for a pair of pants.

Answer:

The system of equations are \left \{ {{8x+4y=176} \atop {3x+4y=116}} \right.

The reasonable price for pair of pants is $20.

Step-by-step explanation:

Let the price of shirt be 'x'.

Let price of pair of pants be 'y'.

Given:

Olivia purchased 8 shirts 4 pairs of pants for $176

So we can say that;

8 multiplied by the price of shirt plus 4 multiplied by the price of pair of  pants is equal to 176.

framing in equation form we get;

8x+4y=176 \ \ \ \ equation \ 1

Also Given:

Raheem purchased 3 shirts and 4 pairs of pants for 116.

So we can say that;

3 multiplied by the price of shirt plus 4 multiplied by the price of pair of pants is equal to 116.

framing in equation form we get;

3x+4y=116 \ \ \ \ equation \ 2

Hence the system of equation are \left \{ {{8x+4y=176} \atop {3x+4y=116}} \right.

Now by using elimination method we will subtract equation 2 from equation 1 we get;

(8x+4y)-(3x+4y)=176-116\\\\8x+4y-3x-4y = 60\\\\5x =60\\\\x=\frac{60}{5}=\$12

Now Substituting the value of x in equation 1 we get;

8x+4y=176\\\\8\times 12+4y =176\\\\96+4y=176\\\\4y =176-96\\\\4y = 80\\\\y= \frac{80}{4} =\$ 20

Hence The reasonable price for pair of pants is $20.

4 0
3 years ago
Se tienen 16 maquinas cuyo rendimiento es del 90% y produce 4800 articulos en 6 dias trabajando 10horas diarias. Si se desea pro
cupoosta [38]

Answer:

5 máquinas.

Step-by-step explanation:

Sabemos que con 16 máquinas, cada una con un rendimiento del 90%, se producen 4800 artículos en 6 días trabajando 10 horas diarias.

Primero extraigamos toda la información útil de esto.

Sea R la velocidad con la que trabaja una máquina con un rendimiento del 100%.

Entonces nuestras máquinas van a trabajar a:

(90%/100%)*R = 0.9*R

16 máquinas juntas trabajaran en total a 16 veces esa cantidad, o:

16*0.9*R

Luego también sabemos que las máquinas trabajan 10 horas al día por 6 días, es decir, trabajan un total de:

6*10h = 60h

60 horas.

Entonces podemos plantear la ecuación:

(16*0.9*R)*60h = 4800 artículos.

Ahora podemos despejar el valor de R.

R = (4800 artículos)/(16*0.9*60 horas) = 5.556 artículos/hora

Ahora:

Se desea producir 1200 artículos.

En 8 días trabajando 9 horas al día, es decir en:

8*9h = 72 horas

Con N máquinas al 60%.

Cada máquina al 60% trabajara con una velocidad de:

0.6*R

N máquinas entonces trabajaran en conjunto a:

N*(0.6*R)

Con la información que se nos da, podemos plantear la ecuación:

N*(0.6*R)*72horas = 1200 artículos.

Queremos resolver esto para N, el número de máquinas, entonces aislamos N

N = (1200 artículos)/((0.6*R)*72horas)

Reemplazando el valor de R, que es 5.556 artículos/hora

N = (1200 artículos)/((0.6*5.556 artículos/hora)*72horas) = 5

Se necesitaran 5 máquinas.

5 0
3 years ago
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